谁能提供一个转换人民币从小写到大写的存储过程?感谢

[lifeforu]

谁能提供一个转换人民币从小写到大写的存储过程?感谢

[pengdali]

/********************************************************
作者：([e-mail])
版本：1.0
创建时间：20020227
修改时间：
功能：小写金额转换成大写
参数：n_LowerMoney 小写金额
v_TransType 种类 -- 1: directly translate, 0: read it in words
输出：大写金额
********************************************************/
CREATE PROCEDURE dbo.L2U
(
@n_LowerMoney numeric(15,2),
@v_TransType int,
@RET VARCHAR(200) output
)
AS

Declare @v_LowerStr VARCHAR(200) -- 小写金额
Declare @v_UpperPart VARCHAR(200)
Declare @v_UpperStr VARCHAR(200) -- 大写金额
Declare @i_I int

set nocount on

select @v_LowerStr = LTRIM(RTRIM(STR(@n_LowerMoney,20,2))) --四舍五入为指定的精度并删除数据左右空格

select @i_I = 1
select @v_UpperStr = ''

while ( @i_I <= len(@v_LowerStr))
begin
select @v_UpperPart = case substring(@v_LowerStr,len(@v_LowerStr) - @i_I + 1,1)
WHEN '.' THEN '元'
WHEN '0' THEN '零'
WHEN '1' THEN '壹'
WHEN '2' THEN '贰'
WHEN '3' THEN '叁'
WHEN '4' THEN '肆'
WHEN '5' THEN '伍'
WHEN '6' THEN '陆'
WHEN '7' THEN '柒'
WHEN '8' THEN '捌'
WHEN '9' THEN '玖'
END
+
case @i_I
WHEN 1 THEN '分'
WHEN 2 THEN '角'
WHEN 3 THEN ''
WHEN 4 THEN ''
WHEN 5 THEN '拾'
WHEN 6 THEN '佰'
WHEN 7 THEN '仟'
WHEN 8 THEN '万'
WHEN 9 THEN '拾'
WHEN 10 THEN '佰'
WHEN 11 THEN '仟'
WHEN 12 THEN '亿'
WHEN 13 THEN '拾'
WHEN 14 THEN '佰'
WHEN 15 THEN '仟'
WHEN 16 THEN '万'
ELSE ''
END
select @v_UpperStr = @v_UpperPart + @v_UpperStr
select @i_I = @i_I + 1
end

--------print '//v_UpperStr ='+@v_UpperStr +'//'

if ( @v_TransType=0 )
begin
select @v_UpperStr = REPLACE(@v_UpperStr,'零拾','零')
select @v_UpperStr = REPLACE(@v_UpperStr,'零佰','零')
select @v_UpperStr = REPLACE(@v_UpperStr,'零仟','零')
select @v_UpperStr = REPLACE(@v_UpperStr,'零零零','零')
select @v_UpperStr = REPLACE(@v_UpperStr,'零零','零')
select @v_UpperStr = REPLACE(@v_UpperStr,'零角零分','整')
select @v_UpperStr = REPLACE(@v_UpperStr,'零分','整')
select @v_UpperStr = REPLACE(@v_UpperStr,'零角','零')
select @v_UpperStr = REPLACE(@v_UpperStr,'零亿零万零元','亿元')
select @v_UpperStr = REPLACE(@v_UpperStr,'亿零万零元','亿元')
select @v_UpperStr = REPLACE(@v_UpperStr,'零亿零万','亿')
select @v_UpperStr = REPLACE(@v_UpperStr,'零万零元','万元')
select @v_UpperStr = REPLACE(@v_UpperStr,'万零元','万元')
select @v_UpperStr = REPLACE(@v_UpperStr,'零亿','亿')
select @v_UpperStr = REPLACE(@v_UpperStr,'零万','万')
select @v_UpperStr = REPLACE(@v_UpperStr,'零元','元')
select @v_UpperStr = REPLACE(@v_UpperStr,'零零','零')
end

-- 对壹元以下的金额的处理
if ( substring(@v_UpperStr,1,1)='元' )
begin
select @v_UpperStr = substring(@v_UpperStr,2,(len(@v_UpperStr) - 1))
end

if (substring(@v_UpperStr,1,1)= '零')
begin
select @v_UpperStr = substring(@v_UpperStr,2,(len(@v_UpperStr) - 1))
end

if (substring(@v_UpperStr,1,1)='角')
begin
select @v_UpperStr = substring(@v_UpperStr,2,(len(@v_UpperStr) - 1))
end

if ( substring(@v_UpperStr,1,1)='分')
begin
select @v_UpperStr = substring(@v_UpperStr,2,(len(@v_UpperStr) - 1))
end

if (substring(@v_UpperStr,1,1)='整')
begin
select @v_UpperStr = '零元整'
end

select @ret=@v_UpperStr

GO

调用过程：

declare @ret varchar(200)

exec L2U 567983.897,1,@ret output

select @ret

[chao778899]

我收集的一个网友写的函数，希望对你有所帮助，如下：
Function Int2Chn(ByVal L_num As Integer) As String
Dim n_data, num, c_data, n_str As String
Dim i, j, k, l As Long
num = L_num
n_data = String(14 - Len(Trim(CStr(Abs(num * 100)))), " ") + Trim(CStr(Abs(num) * 100))
For i = 1 To 14 Step 1
n_str = Mid(n_data, i, 1)
If n_str <> " " Then
If Mid(n_data, i, 2) = "00" Or (n_str = "0" And (i = 4 Or i = 8 Or i = 12 Or i = 14)) Then
Else
c_data = c_data + Trim(Mid("零壹贰叁肆伍陆柒捌玖", CInt(n_str) + 1, 1))
End If
If n_str = "0" And i <> 4 And i <> 8 And i <> 12 Then
Else
c_data = c_data + Trim(Mid("仟佰拾亿仟佰拾万仟佰拾圆角分", i, 1))
End If
If Right(c_data, 4) = "亿万" Then c_data = Left(c_data, Len(c_data) - 1)
End If
Next
If num < 0 Then c_data = "（负数）" + c_data
If num = 0 Then c_data = "零圆"
If n_str = "0" Then c_data = c_data + "整"
Int2Chn = c_data
End Function

[5isoft]

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