请问如何只让在浏览器地栏输入http://local:8080/test/login_init.do有效,而屏蔽系统中其他的....x.do

[jiebao]

请问如何只让在浏览器地栏输入http://local:8080/test/login_init.do有效,而屏蔽系统中其他的....x.do

[whodsow]

用过滤器啊，很简单的嘛

[jiebao]

没有用过"过滤器",请说明如何用"过滤器"?谢谢

[jiebao]

急用,请知道的同志告诉我.谢谢

[whodsow]

test是你的一个应用程序，还是一个应用程序中的子文件夹呀？？

[whodsow]

如下是过滤器类：
package filters;

import java.io.IOException;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpServletRequest;

public class URLFilter implements Filter
{
private FilterConfig config;
protected final static String ALLOW_URI = "/test/login_init.do";
public void init(FilterConfig config)
{
this.config = config;
}
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)throws IOException,ServletException
{
HttpServletRequest httpRequest = (HttpServletRequest)request;
HttpServletResponse httpResponse = (HttpServletResponse)response;
String uri = httpRequest.getServletPath();
if(uri.endsWith(".do"))
{
if(uri.equals(ALLOW_URI))
{
chain.doFilter(request, httpResponse);
return;
}
httpResponse.setStatus(HttpServletResponse.SC_NOT_FOUND);//返回状态码404，未找到请求对象
}
chain.doFilter(request, httpResponse);
}
public void destroy()
{
}
}


在web.xml中再加入如下配置：
<filter>
<filter-name>URLFilter</filter-name>
<description>only /test/login_init.do</description>
<filter-class>filters.URLFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>GBK</param-value>
</init-param>
</filter>


<filter-mapping>
<filter-name>URLFilter</filter-name>
<url-pattern>/test/*</url-pattern>
</filter-mapping>

[whodsow]

既然test是应用程序，改正如下：
package filters;

import java.io.IOException;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpServletRequest;

public class URLFilter implements Filter
{
private FilterConfig config;
protected final static String ALLOW_URI = "/login_init.do";
public void init(FilterConfig config)
{
this.config = config;
}
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)throws IOException,ServletException
{
HttpServletRequest httpRequest = (HttpServletRequest)request;
HttpServletResponse httpResponse = (HttpServletResponse)response;
String uri = httpRequest.getServletPath();
if(uri.endsWith(".do"))
{
if(uri.equals(ALLOW_URI))
{
chain.doFilter(request, httpResponse);
return;
}
config.getServletContext().getNamedDispatcher("login_init.do").forward(request, response);////login_init.do为<servlet-name>
}
chain.doFilter(request, httpResponse);
}
public void destroy()
{
}
}


在web.xml中再加入如下配置：
<filter>
<filter-name>URLFilter</filter-name>
<description>only /test/login_init.do</description>
<filter-class>filters.URLFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>GBK</param-value>
</init-param>
</filter>


<filter-mapping>
<filter-name>URLFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

[whodsow]

不应该这么配置的，应该是：
<filter>
<filter-name>URLFilter</filter-name>
<description>only /login_init.do</description>
<filter-class>filters.URLFilter</filter-class>
</filter>


<filter-mapping>
<filter-name>URLFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

[jiebao]

这样处理,只有login_init.do可以,其它的不行,但正系统正常进入时,其它的也打不开.请指点.

在线等.
谢谢

[jiebao]

test是我的一个应用程序根目录,我发现用以上的方法把所以.do都屏蔽了.是何原因

[jiebao]

httpResponse.setStatus(HttpServletResponse.SC_NOT_FOUND);//返回状态码404，未找到请求对象
我不想返回状态码404，未找到请求对象
, 想让它返回到程序的入口(login_init.do).可以吗?

[pcdll]

把httpResponse.setStatus(HttpServletResponse.SC_NOT_FOUND);改成：
response.sendRedirect("login_init.do")即可

[jiebao]

按照上面的方法屏蔽不了.请指点