关于JSpinner的值的问题？

[0xTonyWang]

我想用JSpinner组件，设置值为时间，比如显示初始时间为08:30，然后每次用上下箭头，均增加或减少一分钟。怎么实现，可否给出代码，谢谢！解决问题的，加分相送。

[rekcah_ph]

修改SpinnerModel
关键这3个方法：
Object getNextValue()
Return the object in the sequence that comes after the object returned by getValue().
Object getPreviousValue()
Return the object in the sequence that comes before the object returned by getValue().
Object getValue()
The current element of the sequence.

[0xTonyWang]

可否详细一点，谢谢

[rekcah_ph]

我刚写了一个，比较粗糙，基本功能都实现了，你可以参考一下。
import javax.swing.*;
class SpinnerTimeModel extends AbstractSpinnerModel
{
int h=0;
int m=0;
public Object getNextValue()
{
System.out.println("getNexValue ");
m++;
if (m == 60)
{
m=0;
h++;
if (h == 24)
h=0;
}
return h+":"+m;
}
public Object getPreviousValue()
{
System.out.println("getPreValue ");
m--;
if (m == -1)
{
m=59;
h--;
if (h==-1)
{
h=23;
}
}
return h+":"+m;
}
public Object getValue()
{
System.out.println("getValue");
return h+":"+m;
}
public void setValue(Object value)
{
System.out.println("setValue " + value + " " + value.getClass());
if (value == null || !(value instanceof String))
{
System.out.println("not instanceof");
throw new IllegalArgumentException("invalid value");
}
else
{
String val = (String)value;
int separator = val.indexOf(':');
String sHour = val.substring(0, separator);
String sMinute = val.substring(separator+1);
try
{
int hour = Integer.parseInt(sHour);
int minute = Integer.parseInt(sMinute);
if (hour>=0 && hour<24 && minute>=0 && minute<60)
{
h = hour;
m = minute;
fireStateChanged();
}
else
{
System.out.println("not 0~23 or 0~59");
throw new IllegalArgumentException("invalid value");
}
}
catch(NumberFormatException nfe)
{
System.out.println("nfe Exception");
throw new IllegalArgumentException("invalid value");
}
}
}
}