关于xml查询的问题。在线等

[csdnye]

<BOOK>
<COVER_IMAGE Source="Huck.gif"/>
<TITLE>The Adventures of Huckleberry Finn</TITLE>
<AUTHOR>Mark Twain</AUTHOR>
<BINDING>mass market paperback</BINDING>
<PAGES>298</PAGES>
<PRICE>$5.49</PRICE>
</BOOK>
<BOOK>
<COVER_IMAGE Source="Leaves.gif"/>
<TITLE>Leaves of Grass</TITLE>
<AUTHOR>Walt Whitman</AUTHOR>
<BINDING>hardcover</BINDING>
<PAGES>462</PAGES>
<PRICE>$7.75</PRICE>
</BOOK>
请问如何得到<COVER_IMAGE>元素的Source属性为"Leaves.gif"的<PAGES>元素的内容
即：462。
小弟刚刚接触xml，谢谢。。。。。。

[asam2183]

Dim node As XmlNode
dim sValue as string
'doc="<root><book>...</book><book>...</book></root>
For Each node In doc.ChildNodes
if node("COVER_IMAGE").Attributes("Source").value="Leaves.gif" then
sValue=node("PAGES").InnerXml '取你想要的节点的值
break
end if
Next

[guoyan19811021]

dim myd as new xml.xmlDoucyment()
dim mys as new io.filestream("xxx.xml",io.filemode.open)
dim myreader as new xml.xmlvalidatingreader(mys,xml.xmlnodetype.Document,Nothing)
myd.load(myreader)
dim x as xml.xmlelement=myreader.getelementbyid("Leaves.gif")
dim y as xml.xmlelement=x.childnodes(0).childnodes(3).value
'page 内容

[saucer]

XmlDocument xmldoc = new XmlDocument();
xmldoc.Load("....");
//XmlNode node = xmldoc.SelectSingleNode("//COVER_IMAGE[@Source = 'Leaves.gif']/../PAGES");
XmlNode node = xmldoc.SelectSingleNode("//BOOK[COVER_IMAGE/@Source = 'Leaves.gif']/PAGES");
if (node != null)
Response.Write(node.InnerText);

[wolve]

楼主都说了啊，我来补充两句。
这个一般用xpath来查询， saucer(思归, .NET MVP)的就是xpath.
("//COVER_IMAGE[@Source = 'Leaves.gif']/../PAGES这里就是xpath的表达式，相关的语法参考w3c