XML的简单读取问题，急！，谢谢!

[JB-Zhang]

有一个结构如下的XML文件，请问怎么把它读进XMLtextReader里面？谢谢
<xml version="1.0" encoding="GB2312">
<unit name="M" type="长度" value="1" />
<unit name="米" type="长度" value="1" />
<unit name="公尺" type="长度" value="1" />
<unit name="CM" type="长度" value="0.01" />
<unit name="厘米" type="长度" value = "0.01" />
<unit name="公分" type="长度" value = "0.01" />
<unit name="MM" type="长度" value = "0.001" />
<unit name="毫米" type="长度" value = "0.001" />
<unit name="KM" type="长度" value = "1000" />
<unit name="千米" type="长度" value = "1000" />
<unit name="公里" type="长度" value = "1000" />
<unit name="里" type="长度" value = "500" />

[雪狼1234567]

DataSet ds=new DataSet("XMLProducts");
//连接SQL Server数据库
SqlConnection conn=new SqlConnection(@"server=glf;uid=sa;pwd=;database=northwind");
SqlDataAdapter da=new SqlDataAdapter("SELECT * FROM products",conn);
//绑定DataGrid控件
da.Fill(ds,"products");
dataGrid1.DataSource=ds;
dataGrid1.DataMember="products";
doc=new XmlDataDocument(ds);
XmlNodeList nodeLst=doc.GetElementsByTagName("ProductName");
//将Xml结点加入item中
foreach(XmlNode nd in nodeLst)
listBox1.Items.Add(nd.InnerText);
//存盘
string file="product.xml";
ds.WriteXml(file);

[雪狼1234567]

using System;
using System.Data.SqlClient;
using System.Data;


class TestMulti
{
public static void Main()
{
string sFileName = "MyTest.xml";

SqlDataAdapter da = new SqlDataAdapter("select * from authors; select * from titles; select * from sales",
"server=localhost;database=pubs;uid=sa;pwd=;");

da.TableMappings.Add("Table","authors");
da.TableMappings.Add("Table1","titles");
da.TableMappings.Add("Table2","sales");

DataSet ds = new DataSet();
da.Fill(ds);

ds.WriteXml(sFileName, XmlWriteMode.WriteSchema);

ds.Dispose();
ds = null;
ds = new DataSet();
ds.ReadXml(sFileName);
foreach (DataTable dt in ds.Tables)
{
Console.WriteLine("{0}, rowcount:{1}", dt.TableName, dt.Rows.Count);
}

}
}

[HapTears]

这个不是有效的xml文件少了</xml>!
如果是有效的xml文件
using System;
using System.IO;
using System.Xml;

//Reads an XML document

public class Sample
{
private const String filename = "items.xml";

public static void Main()
{
XmlTextReader reader = null;

try
{
//Load the reader with the data file and ignore all white space nodes.
reader = new XmlTextReader(filename);
}

finally
{
if (reader!=null)
reader.Close();
}
}

}

[cnhgj]

楼上的，不用加</xml>也是有效的xml文件！

[JB-Zhang]

To HapTears(玻璃*杯) :
我把文件改成合法了，也用XmlTextReader读出来 了，可是就是不知道怎么从reader对象里面读出一个值业

[firejie]

while(reader.read())
{
if(reader.NodeType==XmlNodeType.XmlDeclaration)
{
richTextBox1.AppendText("<?xml version='1.0' encoding='utf-8'?>"+"\n");
}


if(reader.NodeType==XmlNodeType.Element)
{
richTextBox1.AppendText("<"+reader.Name+">");
reader.Read();
}

if(reader.NodeType==XmlNodeType.Element)
{
richTextBox1.AppendText("\n"+"<"+reader.Name+">");
reader.Read();
}


if(reader.NodeType==XmlNodeType.Element)
richTextBox1.AppendText("\n"+"<"+reader.Name+">");
else if(reader.NodeType==XmlNodeType.Text)
richTextBox1.AppendText(reader.Value);
else if(reader.NodeType==XmlNodeType.EndElement)
richTextBox1.AppendText("</"+reader.Name+">"+"\n");

}

[JB-Zhang]

它出现了无效编码的错误了，难道XML不支持中文吗？encoding="GB2312"还不对吗？