请教js正则高手

[zhou1977]

我有个公式串，例如：@JX000001/(@JX000002+@JX000003)，对应的有一个替换数据的数组，例如{'1','2','3'}

怎样用正则表达式替换：@JX000001/(@JX000002+@JX000003)为1/(2+3)？
谢谢

[cloudchen]

<script>
var gongshi = "1,2,3".split(",")
var result = "@JX000001/(@JX000002+@JX000003)".match(/@.{8}/g)
for (var i=0;i<result.length;i++){
result[i]=gongshi[i]
}
alert(result[0])
alert(result[1])
alert(result[2])
</script>

不太灵活，不是很好

[zhou1977]

没有达到我的要求，我要出来的1/(2+3)的字符串

[xuzuning]

<script>
var str = "@JX000001/(@JX000002+@JX000003)";
var gongshi = "1,2,3".split(",")
var result = str.match(/@.{8}/g)
for (var i=0;i<result.length;i++){
str = str.replace(eval("/"+result[i]+"/"),gongshi[i]);
}
alert(str)
</script>

[emu]

var st = "@JX000001/(@JX000002+@JX000003)";
var reg = /@JX00000(\d)/g;
st = st.replace(reg,"$1");
alert(st);

[zhou1977]

我已经自己搞定了，谢谢大家