如何实现一个较大的值的三位一逗号的处理?

[islyb6001]

比如说有1234567和1234567890.12两个数,我想把它们分别处理成如下的CString型
1,234,567和1,234,567,890.12如何实现

[bcpl]

try this:

CString GetCommaNumber(double dValue)
{
COleVariant vValue(dValue);
vValue.ChangeType(VT_BSTR);
CString sValue(vValue.bstrVal);
CString sResult;
CString sFraction;

int nLength = sValue.Find('.');
if(nLength < 1)
{
nLength = sValue.GetLength();
}
else
{
sFraction = sValue.Mid(nLength);
sValue = sValue.Left(nLength);
}

int t = nLength % 3;
if(t)
{
sResult = sValue.Left(t);
if(t != nLength)
sResult += ",";
}

for(int i = t;;)
{
sResult += sValue.Mid(i, 3);
if((i += 3) >= nLength)
break;

sResult += ",";
}
sResult += sFraction;
return sResult;
}

usage:
AfxMessageBox(GetCommaNumber(1234567890.12));

[bluebohe]

我想楼主是想找一个API的函数实现该功能,我也看一下
CString GetCommaNumber(double dValue)
{
static CString str="";
CString str1="",str2="";
str.Format(".%f",dValue-(long)dValue);
while(dValue>1)
{
str1.Format(",%d",((long)dValue)%1000);
dValue=dValue/1000;
str=str1+str;
}
str1.Format("%d",(long)(dValue*1000));
str=str1+str;
return str;
}
赫赫,我不保证正确,因为在网吧

[bluebohe]

改一下
CString GetCommaNumber(double dValue)
{
static CString str="";
CString str1="";
str.Format(".%f",dValue-(long)dValue);
while(dValue>1000)
{
str1.Format(",%d",((long)dValue)%1000);
dValue=dValue/1000;
str=str1+str;
}
str1.Format("%d",(long)(dValue));
str=str1+str;
return str;
}

[bluebohe]

再改一下
CString GetCommaNumber(double dValue)
{
static CString str="";
CString str1="";
str.Format("%f",dValue-(long)dValue);
str=str.Right(str.GetLength()-2);
while(dValue>1000)
{
str1.Format(",%d",((long)dValue)%1000);
dValue=dValue/1000;
str=str1+str;
}
str1.Format("%d",(long)(dValue));
str=str1+str;
return str;
}

[超级管理员9527]

薄荷，买电脑吧，我赞助100分

[bluebohe]

hoho终于有人发铁子了,我又可以改一下拉
我的电脑在女朋友家里,我女朋友的父母过来,于是我到公司宿舍住…………
再改一下
CString GetCommaNumber(double dValue)
{
static CString str="";
CString str1="";
str.Format("%f",dValue-(long)dValue);
str=str.Right(str.GetLength()-1);
while(dValue>1000)
{
str1.Format(",%d",((long)dValue)%1000);
dValue=dValue/1000;
str=str1+str;
}
str1.Format("%d",(long)(dValue));
str=str1+str;
return str;
}