200分求助日期检测问题,高手帮忙

[yacus]

求一个日期检测函数.

一个合法日期的任意左端也合法

如

2000-02-2 合法
2 合法
3 不合法
20 合法
2003 合法
2003-2 合法

函数格式如下

function checkDate (date){
合法返回 true;
}

[007james]

给你个参考：

function sTrim(str){
var i,j,s;
if(str == null){
return '';
}
if(str.length == 0){
return '';
}
for(i = 0;i < str.length;i ++){
if(str.charAt(i) != ' '){
break;
}
}
if(i >= str.length){
return '';
}
for(j = str.length - 1;j >= 0;j --){
if(str.charAt(j) != ' '){
break;
}
}
s = str.substring(i,j + 1);
return s;
}


function IsDate(str1,str2,str3){
if(parseInt(sTrim(str1))){
if(sTrim(str1).length==4){
var yy=parseInt(str1);
var isY=0;
if(((yy%100!=0)&&(yy%4==0))||(yy%400==0)){
isY=1;
}else{
isY=0;
}
if(isY==1){
switch(parseInt(str2)){
case 2:
if(parseInt(str3)>29){
alert("二月没这一天。");
return false;
}
case 4:
if(parseInt(str3)>30){
alert("四月没这一天。");
return false;
}
case 6:
if(parseInt(str3)>30){
alert("六月没这一天。");
return false;
}
case 9:
if(parseInt(str3)>30){
alert("九月没这一天。");
return false;
}
case 11:
if(parseInt(str3)>30){
alert("十一月没这一天。");
return false;
}
};
}else{
switch(parseInt(str2)){
case 2:
if(parseInt(str3)>28){
alert("二月没这一天。");
return false;
}
case 4:
if(parseInt(str3)>30){
alert("四月没这一天。");
return false;
}
case 6:
if(parseInt(str3)>30){
alert("六月没这一天。");
return false;
}
case 9:
if(parseInt(str3)>30){
alert("九月没这一天。");
return false;
}
case 11:
if(parseInt(str3)>30){
alert("十一月没这一天。");
return false;
}
};
}
return true;
}else{
alert("年份为四位数（如:2001）。");
return false;
}
}else{
alert("请输入正确的年份。");
return false;
}
}


function dateKeyEvent(edit) {
var sDate = sTrim(edit.value);
var m_day = new Array();
m_day[0] = 31;
m_day[1] = 28;
m_day[2] = 31;
m_day[3] = 30;
m_day[4] = 31;
m_day[5] = 30;
m_day[6] = 31;
m_day[7] = 31;
m_day[8] = 30;
m_day[9] = 31;
m_day[10] = 30;
m_day[11] = 31;
var ch = sDate.charAt(sDate.length - 1);
if((sDate.length < 5) || ((sDate.length > 5) && (sDate.length < 8)) || ((sDate.length > 8) && (sDate.length < 11))){
if((ch < '0') || (ch > '9')){
edit.value = sDate.substring(0,sDate.length - 1);
return;
}
}
if((sDate.length == 4) || (sDate.length == 7)){
sDate = sDate+"-";
edit.value = sDate;
}
if(sDate.length == 10){
var year = parseInt(sDate.substring(0,4),10);
var month = parseInt(sDate.substring(5,7),10);
if((month > 12) || (month < 1)){
sDate = sDate.substring(0,5);
edit.value = "'"+month+"'";
return;
} else {
var day = parseInt(sDate.substring(8),10);
if(month == 2){
if((year % 400) == 0){
if((day < 1) || (day > (m_day[month - 1] + 1))){
sDate = sDate.substring(0,8);
edit.value = sDate;
return;
}
} else {
if(((year % 4) == 0) && ((year % 100) != 0)){
if((day < 1) || (day > (m_day[month - 1] + 1))){
sDate = sDate.substring(0,8);
edit.value = sDate;
return;
}
} else {
if((day < 1) || (day > (m_day[month - 1]))){
sDate = sDate.substring(0,8);
edit.value = sDate;
return;
}
}
}
} else {
if((day < 1) || (day > m_day[month - 1])){
sDate = sDate.substring(0,8);
edit.value = sDate;
return;
}
}
}
} else {
if(sDate.length > 10){
sDate = sDate.substring(0,10);
edit.value = sDate;
}
}
}

function dateBlurEvent(edit) {
var sDate = sTrim(edit.value);
var m_day = new Array();
m_day[0] = 31;
m_day[1] = 28;
m_day[2] = 31;
m_day[3] = 30;
m_day[4] = 31;
m_day[5] = 30;
m_day[6] = 31;
m_day[7] = 31;
m_day[8] = 30;
m_day[9] = 31;
m_day[10] = 30;
m_day[11] = 31;
var ch;
if(sDate.length != 10){
edit.value = "";
return;
}
for(i = 0;i < 10;i ++){
ch = sDate.charAt(i);
if(((i >= 0) && (i <= 3)) || ((i >= 5) && (i <= 6)) || ((i >= 8) && (i <= 9))){
if((ch < '0') || (ch > '9')){
edit.value = "";
return;
}
} else {
if((i == 4) || (i == 7)){
if(ch != '-'){
edit.value = "";
return;
}
}
}
}
var year = parseInt(sDate.substring(0,4),10);
var month = parseInt(sDate.substring(5,7),10);
var day = parseInt(sDate.substring(8),10);
if((month > 12) || (month < 1)){
edit.value = "";
return;
}
if(month == 2){
if((year % 400) == 0){
if((day < 1) || (day > (m_day[month - 1] + 1))){
edit.value = "";
return;
}
} else {
if(((year % 4) == 0) && ((year % 100) != 0)){
if((day < 1) || (day > (m_day[month - 1] + 1))){
edit.value = "";
return;
}
} else {
if((day < 1) || (day > (m_day[month - 1]))){
edit.value = "";
return;
}
}
}
} else {
if((day < 1) || (day > m_day[month - 1])){
edit.value = "";
return;
}
}
}

[yacus]

楼上的,没符合要求哦.20是合法的.2003-0 也是合法的哦

[gaozyr]

这个用正则比较好些！！
"if(event.srcElement.value!=''){" & _
"var zz=/^(\d{4})[-, ,|,\/,\\,\.,\,](\d{1,2})[-, ,|,\/,\\,\.\,](\d{1,2})$/;" & _
"if(zz.test(event.srcElement.value)){" & _
"var kk=/^(\d{2})$/;" & _
"var strYear=event.srcElement.value.substring(0,4);" & _
"var strMonth=event.srcElement.value.substring(5,7);" & _
"var strDay=event.srcElement.value.substring(event.srcElement.value.length-2,event.srcElement.value.length);" & _
"if(!kk.test(strMonth)){" & _
"strMonth=event.srcElement.value.substring(5,6);}" & _
"if(!kk.test(strDay)){" & _
"strDay=event.srcElement.value.substring(event.srcElement.value.length-1,event.srcElement.value.length);}" & _
"if(strYear<1900||strYear>2099){" & _
"alert('输入日期的年份超出范围！');" & _
"event.srcElement.focus();}" & _
"else{" & _
"if(strMonth<1||strMonth>12){" & _
"alert('输入日期的月份超出范围！');" & _
"event.srcElement.focus();}" & _
"else{" & _
"var strLastDay;" & _
"switch(strMonth){" & _
"case '2':if(strYear%4==0){strLastDay=28;break;}else{strLastDay=29;break;}" & _
"case '4':{strLastDay=30;break;}" & _
"case '6':{strLastDay=30;break;}" & _
"case '9':{strLastDay=30;break;}" & _
"case '11':{strLastDay=30;break;}" & _
"default:{strLastDay=31;break;}}" & _
"if(strDay>strLastDay||strDay==0){" & _
"alert('输入日期超出范围！');" & _
"event.srcElement.focus();}" & _
"else{" & _
"var strDate=new Date(strYear,strMonth-1,strDay);" & _
"if(strDate=='NaN'){" & _
"alert('输入日期的逻辑有误！');" & _
"event.srcElement.focus();}" & _
"else{" & _
"event.srcElement.className='textbox';}" & _
"}" & _
"}" & _
"}" & _
"}" & _
"else{" & _
"alert('请输入正确的日期类型！(YYYY-MM-DD)');" & _
"event.srcElement.focus();}" & _
"}" & _
"else{" & _
"event.srcElement.className='textbox';}"

Output.AddAttribute("onblur", strJS)

通过这个你自已想想就OK了！！

[shyslysky]

function checkDate (date)
{
var strValue = new String();
strValue = date;
var year = new String();
var month = new String();
var day = new String();

switch(strValue.length)
{
case 4:
{
year = strValue;
var testDate = new Date(year,1,1);
return (year == testDate.getFullYear());
break;
}
case 7:
{
if (strValue.charAt(4)!='-')
{
return false;
}
else
{
strValue = value;
year = strValue.substr(0,4);
month = strValue.substr(5,2);
month = month-1;
var testDate = new Date(year,month,1)
return ((year == testDate.getFullYear()) && (month ==testDate.getMonth()));
}
break;

}

case 10:
{
if (strValue.charAt(4)!='-'||strValue.charAt(7)!='-')
{
return false;
}
else
{
year = strValue.substr(0,4);
month = strValue.substr(5,2);
month = month-1;
day = strValue.substr(8,2);
var testDate = new Date(year,month,day)
return ((year == testDate.getFullYear()) && (month ==testDate.getMonth())&&(day == testDate.getDate()));
}

break;
}

default:
return false;

}

}

[yacus]

问题都没有解决哦

[yanfeng]

呵呵，都被别人说了。顶一下

[junyi2003]

关注一下。

[longshenwang]

关注。。。。

[rongwenfeng]

function checkDate( date ) {
if ( date == null || date == "" ) {
return true;
}

var strDate = date;

if (NumberFormat( strDate ))
{

if (strDate.length != 10) {
alert( "错误的日期！" );
return false ;
}

if ( toDateFromString( strDate ) == null ) {
alert("错误的日期！");
return false;
}
}

return true ;
}

function NumberFormat(pstrNum)
{
var strReturn = "";

strNumber = ""+delMoji(pstrNum,"-");

for(var i=0; i<strNumber.length; i++)
{
if (strNumber.charAt(i) >= "0" && strNumber.charAt(i) <= "9")
{

}
else if (strNumber.charAt(i) == "+" || strNumber.charAt(i) == "-" || strNumber.charAt(i) == ".")
{
alert("错误的日期！");
return false;
}
}

return true;
}

function delMoji(pstrMoji, pstrChar)
{
var strReturn ="";
for(var i=0; i<pstrMoji.length; i++)
{
if (pstrMoji.charAt(i) != pstrChar)
{
strReturn = strReturn + pstrMoji.charAt(i);
}
}
return strReturn;
}

function toDateFromString( strDate )
{
var dtDate = null ;
var nYear = parseInt( strDate.substring( 0, 4 ), 10 ) ;
var nMonth = parseInt( strDate.substring( 5, 7 ), 10 ) ;
var nDay = parseInt( strDate.substring( 8, 10 ), 10 ) ;

if( isNaN( nYear ) == true || isNaN( nMonth ) == true || isNaN( nDay ) == true )
{
return null ;
}
dtDate = new Date( nYear, nMonth - 1, nDay ) ;
if( nYear != dtDate.getFullYear() || ( nMonth - 1 ) != dtDate.getMonth() || nDay != dtDate.getDate() )
{
return null ;
}

return dtDate ;
}

[yacus]

谢谢楼上的诸位热心帮助,但是都不能测试通过!不过我受到你们的启发了.^_^

此问题其实超简单!挺有趣的,大家开动脑筋,别按照以往固定的解题思路,可以走捷径的.^_^这个乐趣留给大家,明天告诉大家我的方法.

用户如果依次输入合法日期,函数会检测通过.
如在输入一下数值时都合法:
2
20
200
2003
2003-
2003-2
2003-02
2003-2-6

[piccologoo]

function chkDate(strValue)
{
strValue=new String(strValue);
var Reg;
var iDotPos,iYear,strRight,iMonth,iDay;
Reg=/^(\d{2}|\d{4})\/(\d{1}|\d{2})\/(\d{1}|\d{2})$/;
if(Reg.test(strValue))
{
iDotPos=strValue.search("\/");
iYear=strValue.substring(0,iDotPos);
strRight=strValue.substring(iDotPos+1,strValue.length);
iDotPos=strRight.search("\/");
iMonth=strRight.substring(0,iDotPos);
iDay=strRight.substring(iDotPos+1,strRight.length);
if(iMonth>12||iMonth==0)
{
return false;
}
if(iMonth==2)
{
if (iYear<100) iYear+=2000;
if ((iYear % 4 == 0 && iYear % 100 != 0) || iYear % 400 == 0)
{
if(iDay>29||iDay==0) return false;
}
else
{
if(iDay>28||iDay==0) return false;
}
return true;
}
else if(iMonth==1 || iMonth==3 || iMonth == 5 ||iMonth==7 || iMonth==8 || iMonth==10 || iMonth==12)
{
if(iDay>31||iDay==0)
{

return false;
}
}
else
{
if(iDay>30||iDay==0)
{

return false;
}
}

return true;
}