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分享求助！对日期的检测格式为（yy/mm/dd）,那位大侠给出相应的javascript代码
对日期的检测格式为（yy/mm/dd）希望大家给出相应的javascript代码。
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HopeYan 2003-10-19
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thanks a lot
meizz 2003-10-17
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<script language=javascript>
function strDateTime(str)
{
var r = str.match(/^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2})$/);
if(r==null)return false;
var d= new Date(r[1], r[3]-1, r[4]);
return (d.getYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]);
}
alert(strDateTime("02/01/31"));
alert(strDateTime("03-01-41"));
alert(strDateTime("03/01/41"));
</script>
function strDateTime(str)
{
var r = str.match(/^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2})$/);
if(r==null)return false;
var d= new Date(r[1], r[3]-1, r[4]);
return (d.getYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]);
}
alert(strDateTime("02/01/31"));
alert(strDateTime("03-01-41"));
alert(strDateTime("03/01/41"));
</script>
meizz 2003-10-17
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<script language=javascript>
function strDateTime(str)
{
var r = str.match(/^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2})$/);
if(r==null)return false;
var d= new Date(r[1], r[3]-1, r[4]);
return (d.getYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]);
}
alert(strDateTime("02-01-31"));
alert(strDateTime("03-01-41"));
</script>
function strDateTime(str)
{
var r = str.match(/^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2})$/);
if(r==null)return false;
var d= new Date(r[1], r[3]-1, r[4]);
return (d.getYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]);
}
alert(strDateTime("02-01-31"));
alert(strDateTime("03-01-41"));
</script>
年月日格式判断-正则表达式 YYYY/MM/DD、YYYY/MM/DD| YY/MM/DD、 ^(^(\d{4}|\d{2})(\-|\/|\.)\d{1,2}\3\d{1,2}$)|(^\d{4}…
