有谁能帮个忙呢?解决马上结贴

[HappyDelphiGirl]

有谁能将如下的Oracle转为SQL Server的触发器呢? 在线等待
create or replace trigger tri_classinfo_tmp
after insert on classinfo_tmp for each row
declare
v_cnt number(3);
begin
select count(*) into v_cnt from classinfo
where class_seq=:new.class_seq;
if v_cnt=0 then
insert into classinfo(class_seq,
class_type,
class_name,
manager)
values(:new.class_seq,
:new.class_type,
:new.class_name,
:new.manager
);
else
update classinfo set class_type=:new.class_type,
class_name=:new.class_name,
manager=:new.manager
where class_seq=:new.class_seq;
end if;


end;

[xjwxiong]

試試吧!
語法差不多
可能需要調試

CREATE TRIGGER test ON classinfo_tmp
FOR INSERT
AS
declare @v_cnt smallint
select v_cnt=count(*) from where class_seq= inserted.class_seq
if v_cnt=0
begin
insert into classinfo(class_seq,
class_type,
class_name,
manager)
values( inserted.class_seq,
inserted.class_type,
inserted.class_name,
inserted.manager
)
end
else
begin
update classinfo set class_type=inserted.class_type,
class_name=inserted.class_name,
manager=inserted.manager
where class_seq=inserted.class_seq
end



SQL Server Tigger Example:
USE pubs
IF EXISTS (SELECT name FROM sysobjects
WHERE name = 'employee_insupd' AND type = 'TR')
DROP TRIGGER employee_insupd
GO
CREATE TRIGGER employee_insupd
ON employee
FOR INSERT, UPDATE
AS
/* Get the range of level for this job type from the jobs table. */
DECLARE @min_lvl tinyint,
@max_lvl tinyint,
@emp_lvl tinyint,
@job_id smallint
SELECT @min_lvl = min_lvl,
@max_lvl = max_lvl,
@emp_lvl = i.job_lvl,
@job_id = i.job_id
FROM employee e INNER JOIN inserted i ON e.emp_id = i.emp_id
JOIN jobs j ON j.job_id = i.job_id
IF (@job_id = 1) and (@emp_lvl <> 10)
BEGIN
RAISERROR ('Job id 1 expects the default level of 10.', 16, 1)
ROLLBACK TRANSACTION
END
ELSE
IF NOT (@emp_lvl BETWEEN @min_lvl AND @max_lvl)
BEGIN
RAISERROR ('The level for job_id:%d should be between %d and %d.',
16, 1, @job_id, @min_lvl, @max_lvl)
ROLLBACK TRANSACTION
END

[welyngj]

try:create trigger tri_classinfo_tmp
on classinfo_tmp
after insert
as
begin
declare @v_cnt int

set @v_cnt=( select count(*) c from classinfo c,inserted i
where c.class_seq=i.class_seq)
if @v_cnt=0
insert into classinfo(class_seq,
class_type,
class_name,
manager)
select class_seq,class_type,class_name,manager from inserted

update classinfo set class_type=i.class_type,
class_name=i.class_name,
manager=i.manager from inserted i
where class_seq=i.class_seq

end

[HappyDelphiGirl]

CREATE TRIGGER test ON classinfo_tmp
FOR INSERT
AS
declare @v_cnt smallint
select v_cnt=count(*) from ClassInfo where class_seq= inserted.class_seq
if v_cnt=0
begin
insert into classinfo(class_seq,
class_type,
class_name,
manager)
values( inserted.class_seq,
inserted.class_type,
inserted.class_name,
inserted.manager
)
end
else
begin
update classinfo set class_type=inserted.class_type,
class_name=inserted.class_name,
manager=inserted.manager
where class_seq=inserted.class_seq
end


服务器: 消息 128，级别 15，状态 1，过程 test，行 12
在此上下文中不允许使用 'class_seq'。此处只允许使用常量、表达式或变量。不允许使用列名。

[HappyDelphiGirl]

SQL Server怎么就这么难用呀,我们用Oracle一下子就可以搞定!

[HappyDelphiGirl]

现在最主要的是如何得到插入的这条记录的所有字段值了

[xjwxiong]

可以使用Table Name 做為UPDate 的值
語法:
update classinfo set classinfo.class_type=inserted.class_type,
classinfo.class_name=inserted.class_name,
classinfo.manager=inserted.manager
from inserted ----新加
where classinfo.class_seq=inserted.class_seq
另外:
在Sql Server 中 的變量必須以@ 開頭

試試看!