ASP
上传文件到数据库，如何获得文件名
墨衍会员 · AI 创作全网分发 墨衍智能分发 通过墨衍一键同步至各平台 可同步平台 CSDN微信公众号微博知乎掘金百家号博客园抖音小红书 你的文章也可以这样分发 墨衍会员 ¥399起/年，写一次发全网
我也要 关注 + 加入社区==================浏览文件的代码=============
<form enctype="multipart/form-data" action="addfile.asp" method=post onsubmit="return mysubmit(this)">
<input name="big" type="file" class="button" size="20">
<input name="B3" type="submit" class="button" value="上传">
</form>
==============addfile.asp==================
<!--#include file="../function/conn.inc"-->
<%
dim rs
dim formsize,formdata,bncrlf,divider,datastart,dataend,mydata
formsize=request.totalbytes
formdata=request.binaryread(formsize)
bncrlf=chrB(13) & chrB(10)
divider=leftB(formdata,clng(instrb(formdata,bncrlf))-1)
datastart=instrb(formdata,bncrlf & bncrlf)+4
dataend=instrb(datastart+1,formdata,divider)-datastart
mydata=midb(formdata,datastart,dataend)
Set rs = Server.CreateObject("ADODB.Recordset")
rs.Open "files",conn,3,2
rs.addnew
rs("file_content").appendchunk mydata
rs("test_id")=session("test_id")
rs.update
set rs=nothing
set conn=nothing
session("test_id")=""
response.write "<script>alert('添加成功！');MM_goToURL('self','project_test.asp');</script>"
response.end
%>
==========================================
如果获得上传文件的文件名？？？
<form enctype="multipart/form-data" action="addfile.asp" method=post onsubmit="return mysubmit(this)">
<input name="big" type="file" class="button" size="20">
<input name="B3" type="submit" class="button" value="上传">
</form>
==============addfile.asp==================
<!--#include file="../function/conn.inc"-->
<%
dim rs
dim formsize,formdata,bncrlf,divider,datastart,dataend,mydata
formsize=request.totalbytes
formdata=request.binaryread(formsize)
bncrlf=chrB(13) & chrB(10)
divider=leftB(formdata,clng(instrb(formdata,bncrlf))-1)
datastart=instrb(formdata,bncrlf & bncrlf)+4
dataend=instrb(datastart+1,formdata,divider)-datastart
mydata=midb(formdata,datastart,dataend)
Set rs = Server.CreateObject("ADODB.Recordset")
rs.Open "files",conn,3,2
rs.addnew
rs("file_content").appendchunk mydata
rs("test_id")=session("test_id")
rs.update
set rs=nothing
set conn=nothing
session("test_id")=""
response.write "<script>alert('添加成功！');MM_goToURL('self','project_test.asp');</script>"
response.end
%>
==========================================
如果获得上传文件的文件名？？？
...全文
