C++中如何实现Press any Key to continue功能

54lem 2003-10-29 06:36:38

不用 conio.h 里面的 getch() getche()

如何实现按任意键执行下一步操作的功能

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AkiraChing 2003-12-16

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cout<<"Press any Key to continue";
cin.ignore();

AkiraChing 2003-10-29

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cout<<"Press any Key to continue";
getchar();

beyondtkl 2003-10-29

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确实.

54lem 2003-10-29

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是控制台程序
我想用标准 C++ 库来实现

标准 C++ 库没有 conio.h (属于 C 函数库）头文件
可能确实没有办法了
哎

redleaf0000 2003-10-29

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如果是控制台程序可以用_getch函数等待用户按键
要是图形界面程序的话似乎只能用模式对话框了

54lem 2003-10-29

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用上了API了呀
就用标准 C++ 运行库难道不能解决？

carbon107 2003-10-29

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if (pMsg.message== WM_KEYDOWN)

carbon107 2003-10-29

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PreTranslateMessage(MSG* pMsg)
{
if (pMsg.== WM_KEYDOWN)
AfxMessageBox("haha");
}
捕获消息

54lem 2003-10-29

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有没有 C++ 标准库里面的函数可以解决这个问题？

如果没有，应该怎样做才能实现同样的功能呀

yaoha2003 2003-10-29

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是个难题，UP

汉诺塔算法 C++ 有截图结果如下: 请输入盘子数：4 各步骤如下： A-->B A-->C B-->C A-->B C-->A C-->B A-->B A-->C B-->C B-->A C-->A B-->C A-->B A-->C B-->C 总步骤数为：15 Press any key to continue

guessing and betting number game The user starts with 100 dollars, and is able to bet and guess until they quit or have no more money. In each turn, they are asked for a bet. If they enter 0, then the program should give a farewell message and quit. The bet must be positive and within their available balance, If they enter incorrectly, the program should set the bet to their balance and tell them this. Once a bet is entered, they must pick a number between 1 and 10 (you do not need to errorcheck or correct this). This guess is then compared to a number the computer randomly generates each time (also between 1 and 10). If the guess is correct, the user wins the amount of their bet. If the guess is incorrect, the user will lose their bet divided by 5 and multiplied by the distance from the correct number - e.g. if the bet is 50, the computer’s number is 5 and the user guesses 7, then the user will lose 20 dollars( 50/5 * (7-5) = 20 ). However, they should not lose more than their balance, so if their balance is 50, the bet is 40, the computer’s number is 1 and the user guesses 10, (40/5 * (10-1) = 72 > 50 )then they should lose 50. After each turn, the program should display that turn's winnings (or loss amount) and the new balance,and then repeat the game until the user either quits or has no money left. Dollar values should be formatted in the standard way with two decimal places and a $ in front. Sample output from the program is below. You should make your program match this exactly (except for your name). An appropriate welcome message with your name in it should be shown at the start of the program. Assignment 1 : Guessing Game Written by yourname Please enter your bet (up to $100.00): $50 Guess a number between 1 and 10: 5 Correct! You win $50.00 Your new balance is $150.00 Please enter your bet (up to $150.00): $200 Your bet is $150.00 Guess a number between 1 and 10: 6 Wrong! The computer chose: 4 You lose $60.00 Your new balance is $90.00 Please enter your bet (up to $90.00): $80 Guess a number between 1 and 10: 1 Wrong! The computer chose: 7 You lose $90.00 Thank you for playing! Press any key to continue . . . Another Sample: CP1200 Guessing Game Written by Lindsay Ward Please enter your bet (up to $100.00): $-20 Your bet is $100.00 Guess a number between 1 and 10: 5 Wrong! The computer chose: 2 You lose $60.00 Your new balance is $40.00 Please enter your bet (up to $40.00): $10.50 Guess a number between 1 and 10: 12 Wrong! The computer chose: 2 You lose $21.00 Your new balance is $19.00 Please enter your bet (up to $19.00): $0 Thank you for playing! Press any key to continue . . . srand( static_cast(time(0))) ; 初始化 computerNumber = 1 + rand( ) % 10 ; 产生随机数 cout << fixed << setprecision(2) ; 控制输出显示2位小数

综合多门教材摘取通用模块功能函数都存为txt格式并附有运行结果例如：二叉搜索算法 #include<iostream h> int index int int[] int ; int main { int a[] {22 33 44 55 66 77 88}; cout<<"index 44 a 7 "<<index 44 a 7 <<endl; cout<<"index 60 a 7 "<<index 60 a 7 <<endl; } int index int x int a[] int n { int lo 0 hi n 1 i; while lo< hi {i lo+hi 2; if a[i] x return i; if a[i]<x lo i+1; continue search in a[i+1 hi] else continue search in a[lo i 1] hi i 1; } return n; x was not found in a[0 n 1] } index 44 a 7 2 index 60 a 7 7 Press any key to continue">综合多门教材摘取通用模块功能函数都存为txt格式并附有运行结果例如：二叉搜索算法 #include<iostream h> int index int int[] int ; int main { int a[] {22 33 44 55 66 77 88}; cout<<"index 44 a 7 "<<index 44 a 7 <<endl [更多]

简单来说就是暂停的意思，一般在LINUX编程时会用到，等待接收信号，才会重新运行。在进行C/C++编程的时候，在运行程序查看输出效果时，会出现窗口闪一下就关闭的情况。在C语言中一般通过添加getchar(); 在C++中一般在main函数中的return之前添加system(“pause”);这样就可以看清楚输出的结果，pause会输出”press any key to continue. . .”。 system函数原型为 int system(char *command)，在windows平台就是执行DOS命令，在linux平台就是执行shell命令 Linux下system ()

实现一个能够“走秒”的时钟模拟程序 class Clock { private: int Hour, Minute, Second; public: void SetTime (int NewH, int NewM, int NewS); void Tick(); //走秒 void ShowTime(); int GetHour(); int GetMinute(); int GetSecond(); }; 输入输出样例：请输入时间（时分秒）：23 59 45（回车）请输入测试时长（分）：3（回车）时间是 23:59:45 //（这里在相同的位置//显示从23时59分45秒到00时02分45秒）还要继续测试吗（Y/N）？Y（回车）请输入时间（时分秒）：2 5 3（回车）请输入测试时长（分）：2（回车）时间是 02:05:03 //（这里在相同的位置//显示从02时05分03秒到02时07分03秒）还要继续测试吗（Y/N）？N（回车）程序结束了，再见！ Press any key to continue

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