window.open?

andylihero 2003-11-05 10:49:52

怎样控制用window.open打开的窗口在屏幕上显示的位置？

比如，我想用window.open打开一个窗口，可是打开的窗口在屏幕的右上角，我想让他显示在屏幕中央该怎么做？谢谢

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zyzy15 2003-11-05

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忘了你要用window.open :P

<body onLoad="resizewindow()">

<script>
<!--
function resizewindow(){
newwin=window.open("","","scrollbars");
newwin.moveTo(0,screen.height/4);
newwin.resizeTo(screen.width,screen.height/2);
newwin.location="http://jt1.126.com";
}
</script>

</body>

zyzy15 2003-11-05

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看看这个： :)
<html>
<body onLoad="resizewindow()">

<script>
function resizewindow(){
window.moveTo(0,screen.height/4);
window.resizeTo(screen.width,screen.height/2);
window.location="http://www.126.com";
}
</script>

</body>
</html>

YQShi 2003-11-05

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<SCRIPT language="javascript">
function popwin2(url)
{
var WIN_WIDTH,WIN_HEIGHT;
WIN_WIDTH=500; //弹出窗体的宽
WIN_HEIGHT=400; //弹出窗体的高
var newwin=window.open(url,"newwindow","toolbar=0,location=0,directories=0,z-lock=0,status=0,menubar=0,resizable=0,scrollbars=0,width="+WIN_WIDTH+",height="+WIN_HEIGHT+",top="+(window.screen.availHeight/2-WIN_HEIGHT/2)+",left="+(window.screen.availWidth/2-WIN_WIDTH/2)+"");
newwin.focus();
return;
}
</SCRIPT>
调用时比如:
<INPUT NAME="Button" TYPE="BUTTON" VALUE="Test" onclick="popwin2('UserBack/Back.asp')">