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怎么查找出重复记录!

shuichong 2003-12-10 04:53:42
表sbsj里有记录2000条
按照bm,sb这二个字段为唯一:
select distinct bm,sb from sbsj
得到的记录是1900条

怎样得到这100条重复的记录???
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select * from sbsj a
where (select sum(1) from sbsj where bm=a.bm and sb=a.sb)>1
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playyuer 2003-12-10
select *
from sbsj a
where (select count(*) from sbsj where bm = a.bm and sb = a.sb) > 1
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CrazyFor 2003-12-10
如果有ID字段,就是具有唯一性的字段

delect table where id not in (

select max(id) from table group by col1,col2,col3...
)
group by 子句后跟的字段就是你用来判断重复的条件,如只有col1,那么只要col1字段内容相同即表示记录相同。



2,如果是判断所有字段也可以这样
select * into #aa from table group by id1,id2,....
delete table
insert into table
select * from #aa



3,没有ID的情况

select identity(int,1,1) as id,* into #temp from tabel
delect # where id not in (
select max(id) from # group by col1,col2,col3...)
delect table
inset into table(...)
select ..... from #temp


col1+','+col2+','...col5 联合主键


select * from table where col1+','+col2+','...col5 in (

select max(col1+','+col2+','...col5) from table
where having count(*)>1
group by col1,col2,col3,col4
)
group by 子句后跟的字段就是你用来判断重复的条件,如只有col1,那么只要col1字段内容相同即表示记录相同。

2,
select identity(int,1,1) as id,* into #temp from tabel
select * from #temp where id in (
select max(id) from #emp where having count(*)>1 group by col1,col2,col3...)
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txlicenhe 2003-12-10
select a.bm,a.sb from sbsj a
join (select bm,sb from sbsj group by bm,sb having count(*) > 1) b
on a.bm = b.bm and a.sb = b.sb
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创建于2007-09-28

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