有关数据库加密的问题

[thinkoversky]

如何加密数据库，要用到什么知识，如何操作？

[lynx1111]

数据库不能加密，设置好权限，保护好密码就行了
试图和存储过程可以加密，但是也可以解密：
加密：
create procedure aaa
with ENCRYPTION
as
select * from test
GO


解密：

------------------------sql2000大于40000的-----------------
原作：j9988 号:J老师
create PROCEDURE sp_decrypt(@objectName varchar(50))
AS
begin
declare @objectname1 varchar(100),@orgvarbin varbinary(8000)
declare @sql1 nvarchar(4000),@sql2 nvarchar(4000),@sql3 nvarchar(4000),@sql4 nvarchar(4000),@sql5 nvarchar(4000),@sql6 nvarchar(4000),@sql7 nvarchar(4000),@sql8 nvarchar(4000),@sql9 nvarchar(4000),@sql10 nvarchar(4000)
DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
declare @i int,@status int,@type varchar(10),@parentid int
declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int
select @obj_type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)

create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)
insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)
select @number=max(number) from #temp
set @k=0

while @k<=@number
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
begin
if @type='P'
set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'ALTER PROCEDURE '+ @objectName+' WITH ENCRYPTION AS '
end)

if @type='TR'
set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '

if @type='FN' or @type='FN' or @type='FN'
set @sql1=(case @type when 'TF' then
'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns table with encryption as return select @a as a'
end)

if @type='V'
set @sql1='ALTER VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 '

set @q=len(@sql1)
set @sql1=@sql1+REPLICATE('-',4000-@q)
select @sql2=REPLICATE('-',4000),@sql3=REPLICATE('-',4000),@sql4=REPLICATE('-',4000),@sql5=REPLICATE('-',4000),@sql6=REPLICATE('-',4000),@sql7=REPLICATE('-',4000),@sql8=REPLICATE('-',4000),@sql9=REPLICATE('-',4000),@sql10=REPLICATE('-',4000)
exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10)
end
set @k=@k+1
end

set @k=0
while @k<=@number
begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
begin
select @colid=max(colid) from #temp where number=@k
set @n=1

while @n<=@colid
begin
select @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp WHERE colid=@n and number=@k

SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectName) and colid=@n and number=@k)
if @n=1
begin
if @type='P'
SET @OrigSpText2=(case when @number>1 then 'CREATE PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'CREATE PROCEDURE '+ @objectName +' WITH ENCRYPTION AS '
end)


if @type='FN' or @type='FN' or @type='FN'
SET @OrigSpText2=(case @type when 'TF' then
'CREATE FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'CREATE FUNCTION '+ @objectName+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'CREATE FUNCTION '+ @objectName+'(@a char(1)) returns table with encryption as return select @a as a'
end)

if @type='TR'
set @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '

if @type='V'
set @OrigSpText2='CREATE VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 '

set @q=4000-len(@OrigSpText2)
set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)
end
else
begin
SET @OrigSpText2=REPLICATE('-', 4000)
end
--start counter
SET @i=1
--fill temporary variable
SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2))

--loop
WHILE @i<=datalength(@OrigSpText1)/2
BEGIN

SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^
(UNICODE(substring(@OrigSpText2, @i, 1)) ^
UNICODE(substring(@OrigSpText3, @i, 1)))))
SET @i=@i+1
END
set @orgvarbin=cast(@OrigSpText1 as varbinary(8000))
set @resultsp=(case when @encrypted=1
then @resultsp
else convert(nvarchar(4000),case when @status&2=2 then uncompress(@orgvarbin) else @orgvarbin end)
end)
print @resultsp
--execute( @resultsp)
set @n=@n+1

end

end
set @k=@k+1
end

drop table #temp
end

适合40000字符。
每次4000　print出来，自已贴。
切记：我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!!
超过40000的，自已加SQL（我上面用SQL.SQL2－－SQL10）
超长的可加SQL11--sql20........


字段也可以加密：
eclare @logintable table(username varchar(20),passwd varbinary(256))
insert @logintable(username,passwd) values('yourname',pwdencrypt('123456'))

declare @pwd varbinary(256)

select @pwd=passwd from @logintable where username='yourname'
--比较：
if pwdcompare('12356',@pwd)=1
print 'true'
else
print 'false'

select * from @logintable

[txlicenhe]

SQL数据库是没法加密的。

[Arionma]

To: lynx1111(任我行:CrazyEnglishing)
你贴的代码有没有测试过，好像有点问题。最好能够加注释。