请教一下关于时间的函数

[ghost986212]

如现在的系统时间为2003/12/12 16:30

怎么样把这个时间转化为200312121630 ？

如果有相同的有如何在后面加个识别数字把它区别开来，如20031212163001。

这样的代码怎么写啊？？

[swich]

year(date())&month(date())&day(date())&hour(date())&minute(date())

[luluso]

分别取出然后&就行了。

[jnyezhi]

year(now())+month(now())+day(now())+hour(now())+minute(now())+Rnd

[shleo]

这样也可以
time1=now()
time2=mid(time1,1,4)&mid(time1,6,2)&mid(time1,9,2)&mid(time1,12,2)&mid(time1,15,2)&mid(time1,18,2)
Response.Write time2

[shleo]

取系统时间怎么会取出一样的系统时间？？

[troopers]

都说了

[mingchuan]

dim time1,time2
time1=now()
time2=year(time1)&month(time1)&day(time1)&hour(time1)&minute(time1)

[61]

year(now())&month(now())&day(now())&hour(now())&minute(now())