50分求一条sql语句

[zjh13226]

table
id bdate
1 2003-10-15 15:15:25
2 2003-10-10 15:5:42
1 2003-10-11 15:15:05
2 2003-10-04 15:5:07
1 2003-10-10 15:2:51
3 2003-09-12 15:7:01
1 2003-10-17 15:4:30
我怎样取出不同id中最早的时间
比如按以上表应反回
1 2003-10-17 15:4:30
2 2003-10-10 15:5:42
3 2003-09-12 15:7:01

[bzscs]

select distinct [id],bdate from table order by id asc

[bzscs]

select distinct [id],bdate from table order by id asc,bdate desc

[snowcloud2002]

select distinct max(datediff('s',bdate,now()) from table1

这样不知道可以不?

[snowcloud2002]

select distinct [id] max(datediff('s',bdate,now()) from table1

[Programmersheaven]

select distinct [id],bdate from table order by id asc,bdate ASC

[lint]

1、select id,max(date) from table group by id
2、update table set user=replace(replace(replace(user,',ay,',',') ,',ay',''),'ay,','')

[zjh13226]

以上问题小弟已经解决，现又有一个新问题
　怎样在类型为字符串的字段中减去一些值
表
　id user
1 ff,ay
2 er,at
3 aw,au
4 sf,ad,ae
5 er,ay,ae
假设我要去掉用户中的ay，则表的内容应为
　id user
1 ff,
2 er,at
3 aw,au
4 sf,ad,ae
5 er,ae

[zjh13226]

在ACCESS中REPLACE不能用呀，还有没有其他办法。