求一个能产生4位随机数的beans(急在线等)

[zhaoweiwei]

求一个能产生4位随机数的beans

[zhaoweiwei]

有人么？

[jimaojian]

Random r=new Random();

1000+(9999-1000)*r.nextfloat();

[catzm]

public int getRandom(){
int returnValue = 0;
try{
Random random_1 = new Random();
returnValue = random_1.nextInt(9999);
if (returnValue < 1000){
returnValue = returnValue + 1000;
}
}catch(Exception e){
e.printStackTrace();
}
return returnValue;
}

[Jass]

int rand = 1000+9000*(new java.math.Random().nextFloat());

[myblessu]

public static String getRandomString(int size){
String seed="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
byte chs[] = seed.getBytes();
byte bs[] = new byte[size];
Random random = new Random();
int length = chs.length;
for(int i = 0; i < size; i++){
bs[i]=chs[random.nextInt(length)];
}
return new String(bs);
}

[zjwxcn]

不错，学习中ing...

[weichenggao]

支持，关注！

[色老虫]

这么多，哪个好？？我也拣一个用用：）

[nql10]

都好啊！！！

[sandyen]

/**
* 取得随机数（附加码）
* @return 四位的数字随机数
*/
public static String getRandomNum(int num)
{
String[] digits = {"1","2","3","4","5","6","7","8","9","0"};
Random rnum = new Random(new Date().getTime());

for(int i = 0; i < digits.length; i++)
{
int index = Math.abs(rnum.nextInt()) % 10;
String tmpDigit = digits[index];
digits[index] = digits[i];
digits[i] = tmpDigit;
}

String returnStr = digits[0];
for (int i = 1; i < num; i++)
{
returnStr = digits[i] + returnStr;
}
return returnStr;
}