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sql语句怎么连接数字类型变量？
declare @Strsql varchar(2000),@iagefrom int,@iageto int
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '''+iagefrom+''' and '''+iageto+''''
--这样不行
--这种方法只适合字符串类型的变量，但数字类型的变量有问题，数字类型的 变量该怎么连接呢？
exec(@Strsql)
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '''+iagefrom+''' and '''+iageto+''''
--这样不行
--这种方法只适合字符串类型的变量，但数字类型的变量有问题，数字类型的 变量该怎么连接呢？
exec(@Strsql)
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hmily1688 2003-12-23
就是cast或convert进行转换
具体用法可以查帮助
具体用法可以查帮助
gmlxf 2003-12-23
declare @Strsql varchar(2000),@iagefrom int,@iageto int
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '+cast(@iagefrom as varchar)+' and '+cast(@iageto as varchar)
exec(@Strsql)
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '+cast(@iagefrom as varchar)+' and '+cast(@iageto as varchar)
exec(@Strsql)
devilwind 2003-12-23
declare @Strsql varchar(2000),@iagefrom int,@iageto int
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '+cast(@iagefrom as varchar(10))+' and '+cast(@iageto as varchar(10))
select @Strsql
exec(@Strsql)
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '+cast(@iagefrom as varchar(10))+' and '+cast(@iageto as varchar(10))
select @Strsql
exec(@Strsql)
gmlxf 2003-12-23
declare @Strsql varchar(2000),@iagefrom int,@iageto int
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '+cast(@iagefrom as varchar)+' and '+cast(@iageto as varchar)
print @Strsql
set @iagefrom=25
set @iageto=100
set @Strsql='select * from members where age between '+cast(@iagefrom as varchar)+' and '+cast(@iageto as varchar)
print @Strsql