3)如何取得某个月的天数
declare @m int
set @m=2 --月份
select datediff(day,'2003-'+cast(@m as varchar)+'-15' ,'2003-'+cast(@m+1 as varchar)+'-15')
另外,取得本月天数
select datediff(day,cast(month(GetDate()) as varchar)+'-'+cast(month(GetDate()) as varchar)+'-15' ,cast(month(GetDate()) as varchar)+'-'+cast(month(GetDate())+1 as varchar)+'-15')
或者使用计算本月的最后一天的脚本,然后用DAY函数区最后一天
SELECT Day(dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate())+1, 0)))
4)判断是否闰年:
SELECT case day(dateadd(mm, 2, dateadd(ms,-3,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)))) when 28 then '平年' else '闰年' end
或者
select case datediff(day,datename(year,getdate())+'-02-01',dateadd(mm,1,datename(year,getdate())+'-02-01'))
when 28 then '平年' else '闰年' end
5)一个季度多少天
declare @m tinyint,@time smalldatetime
select @m=month(getdate())
select @m=case when @m between 1 and 3 then 1
when @m between 4 and 6 then 4
when @m between 7 and 9 then 7
else 10 end
select @time=datename(year,getdate())+'-'+convert(varchar(10),@m)+'-01'
select datediff(day,@time,dateadd(mm,3,@time))
select convert(varchar(10),dateadd(day,-datepart(dd,getdate())+1,getdate()),120) as field1
select convert(varchar(10),dateadd(day,-datepart(dd,getdate()),dateadd(mm,1,getdate())),120) as field2