疑问,请PHP高手帮助
我定义了一个对象,如下:
class SpConfig
{
var $mId;
var $mName;
var $mDescription;
var $mOrdertype;
var $mFtpdir;
var $mHost;
var $mPort;
var $mUser;
var $mPwd;
var $mSmtpmail;
var $mHttpurl;
function SpConfig($id, $name, $description, $ordertype, $ftpdir, $host, $port, $user, $pwd, $smtpmail, $httpurl)
{
$this->$mId=$id;
$this->$mName=$name;
$this->$mDescription=$description;
$this->$mOrdertype=$ordertype;
$this->$mFtpdir=$ftpdir;
$this->$mHost=$host;
$this->$mPort=$port;
$this->$mUser=$user;
$this->$mPwd=$pwd;
$this->$mSmtpmail=$smtpmail;
$this->$mHttpurl=$httpurl;
}
function toString()
{
$str = "id=$mId,"
."name=$mName,"
."description=$mDescription,"
."ordertype=$mOrdertype,"
."ftpdir=$mFtpdir,"
."host=$mHost,"
."port=$mPort,"
."user=$mUser,"
."pwd=$mPwd,"
."smtpmail=$mSmtpmail,"
."httpurl=$mHttpurl" ;
return $str;
}
};
然后构造一个实例 ($row 里面有数据)
$tmp = new SpConfig($row[0],$row[1],$row[2],$row[3],$row[4],$row[5],$row[6],$row[7],$row[8],$row[9],$row[10]);
echo "new SpConfig, ".$tmp->toString()."<br>";
但打印结果new SpConfig, id=,name=,description=,ordertype=,ftpdir=,host=,port=,user=,pwd=,smtpmail=,httpurl=
全是空。