急!如何读取SQL里面的image字段,显示于网页?

轻舟已过万重山 2004-01-05 03:32:32
如何读取SQL里面的image字段,显示于网页?
如何把image控件里的图片写入SQL?
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还是有点问题:谈谈吧,如何把图片读出来显示在image上,讲讲原理方法也行.
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Thanks!
acewang 2004-01-05
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向SQL Server数据库添加图片
作者: 孟宪会 出自: 【孟宪会之精彩世界】 发布日期: 2003-6-20 19:26:46
--------------------------------------------------------------------------------

下面的代码实现向SQL Server数据库添加图片和文字的功能。

首先,在SQL查询分析器中执行下面的语句,以创建表和存储过程。

Drop Table Person

Go
Create Table Person
(
PersonID Int Identity,
PersonEmail Varchar(255),
PersonName Varchar(255),
PersonSex Char(1),
PersonDOB DateTime,
PersonImage Image,
PersonImageType Varchar(255)
)

Drop Proc sp_person_isp

Go
Create Proc sp_person_isp
@PersonEmail Varchar(255),
@PersonName Varchar(255),
@PersonSex Char(1),
@PersonDOB DateTime,
@PersonImage Image,
@PersonImageType Varchar(255)
As
Begin
Insert into Person
(PersonEmail, PersonName, PersonSex,
PersonDOB, PersonImage, PersonImageType)
Values
(@PersonEmail, @PersonName, @PersonSex,
@PersonDOB, @PersonImage, @PersonImageType)
End

Go

下面就是完整的代码,拷贝即可运行:

<%@ Import Namespace="System.IO" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<%@ Import Namespace="System.Data" %>
<%@ Page Language="vb" %>
<HTML>
<HEAD>
<title>向SQL Server插入图片</title>
<script runat="server">
Public Sub AddPerson(sender As Object, e As EventArgs)
Dim intImageSize As Int64
Dim strImageType As String
Dim ImageStream As Stream
' 获得图片的大小
intImageSize = PersonImage.PostedFile.ContentLength
' 获得图片类型
strImageType = PersonImage.PostedFile.ContentType
'读取图片
ImageStream = PersonImage.PostedFile.InputStream
Dim ImageContent(intImageSize) As Byte
Dim intStatus As Integer
intStatus = ImageStream.Read(ImageContent, 0, intImageSize)
' 创建Connection和Command对象
Dim strCnn As String = "Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;"
Dim myConnection As New SqlConnection(strCnn)
Dim myCommand As New SqlCommand("sp_person_isp", myConnection)
' 使用存储过程
myCommand.CommandType = CommandType.StoredProcedure
' 向存储过程添加参数
Dim prmEmail As New SqlParameter("@PersonEmail", SqlDbType.VarChar, 255)
prmEmail.Value = txtPersonEmail.Text
myCommand.Parameters.Add(prmEmail)

Dim prmName As New SqlParameter("@PersonName", SqlDbType.VarChar, 255)
prmName.Value = txtPersonName.Text
myCommand.Parameters.Add(prmName)
Dim prmSex As New SqlParameter("@PersonSex", SqlDbType.Char, 1)

If sexMale.Checked Then
prmSex.Value = "M"
Else
prmSex.Value = "F"
End If
myCommand.Parameters.Add(prmSex)

Dim prmPersonDOB As New SqlParameter("@PersonDOB", SqlDbType.DateTime)
prmPersonDOB.Value = txtPersonDob.Text
myCommand.Parameters.Add(prmPersonDOB)

Dim prmPersonImage As New SqlParameter("@PersonImage", SqlDbType.Image)
prmPersonImage.Value = ImageContent
myCommand.Parameters.Add(prmPersonImage)

Dim prmPersonImageType As New SqlParameter("@PersonImageType", SqlDbType.VarChar, 255)
prmPersonImageType.Value = strImageType
myCommand.Parameters.Add(prmPersonImageType)

Try
myConnection.Open()
myCommand.ExecuteNonQuery()
myConnection.Close()
Response.Write("添加成功!")
Catch SQLexc As SqlException
Response.Write("添加失败,原因:" & SQLexc.ToString())
End Try
End Sub
</script>
</HEAD>
<body style="FONT: 9pt 宋体">
<form enctype="multipart/form-data" runat="server" ID="Form1">
<asp:Table Runat="server" Width="50%" BorderWidth="1" BackColor="Beige" ID="Table1"
Font-Name="宋体" Font-Size="9pt">
<asp:TableRow>
<asp:TableCell ColumnSpan="2" BackColor="#ff0000">
<asp:Label ForeColor="#ffffff" font-bold="True" Runat="server" Text="添加新用户" ID="Label1" />
</asp:TableCell>
</asp:TableRow>
<asp:TableRow>
<asp:TableCell HorizontalAlign="Right">
<asp:Label Runat="server" Text="姓名" ID="Label2" />
</asp:TableCell>
<asp:TableCell>
<asp:TextBox id="txtPersonName" Runat="server" />
</asp:TableCell>
</asp:TableRow>
<asp:TableRow>
<asp:TableCell HorizontalAlign="Right">
<asp:Label Runat="server" Text="电子邮件" ID="Label3" />
</asp:TableCell>
<asp:TableCell>
<asp:TextBox id="txtPersonEmail" Runat="server" />
</asp:TableCell>
</asp:TableRow>
<asp:TableRow>
<asp:TableCell HorizontalAlign="Right">
<asp:Label Runat="server" Text="性别" ID="Label4"/>
</asp:TableCell>
<asp:TableCell>
<asp:RadioButton GroupName="sex" Text="男" ID="sexMale" Runat="server" />
<asp:RadioButton GroupName="sex" Text="女" ID="sexFeMale" Runat="server" />
</asp:TableCell>
</asp:TableRow>
<asp:TableRow>
<asp:TableCell HorizontalAlign="Right">
<asp:Label Runat="server" Text="出生日期" ID="Label5"/>
</asp:TableCell>
<asp:TableCell>
<asp:TextBox id="txtPersonDOB" Runat="server" />
</asp:TableCell>
</asp:TableRow>
<asp:TableRow>
<asp:TableCell HorizontalAlign="Right">
<asp:Label Runat="server" Text="照片" ID="Label6"/>
</asp:TableCell>
<asp:TableCell>
<input type="file" id="PersonImage" runat="server" NAME="PersonImage" /></asp:TableCell>
</asp:TableRow>
<asp:TableRow>
<asp:TableCell ColumnSpan="2" HorizontalAlign="Center">
<asp:Button Text=" 添 加 " OnClick="AddPerson" Runat="server" ID="Button1"/>
</asp:TableCell>
</asp:TableRow>
</asp:Table>
</form>
</body>
</HTML>
acewang 2004-01-05
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转孟子:
从SQL Server数据库提取图片并显示在DataGrid
作者: 孟宪会 出自: 【孟宪会之精彩世界】 发布日期: 2003-6-20 19:27:10
--------------------------------------------------------------------------------

下面的代码实现从SQL Server数据库提取图片并显示在DataGrid的功能。

下面就是完整的代码,拷贝即可运行:

<%@ Page Language="vb" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<html>
<head>
<title>用户列表</title>
<script runat=server>
Sub Page_Load(sender As Object, e As EventArgs)
If Not Page.IsPostBack Then
BindGrid()
End If
End Sub

Private Sub BindGrid()
Dim strCnn As String = "Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;"
Dim myConnection As SqlConnection = New SqlConnection(strCnn)
Dim myCommand As SqlCommand = New SqlCommand("SELECT * FROM Person", myConnection)
myCommand.CommandType = CommandType.Text
Try
myConnection.Open()
DG_Persons.DataSource = myCommand.ExecuteReader(CommandBehavior.CloseConnection)
DG_Persons.DataBind()
Catch SQLexc As SqlException
Response.Write("Error occured while Generating Data. Error is " & SQLexc.ToString())
End Try
End Sub

Function FormatURL(strArgument) as String
Return ("ReadImage.aspx?id=" & strArgument)
End Function
</script>
</head>
<body style="font: 9pt 宋体">
<h3 align=center>从数据库中取得照片并显示在DataGrid中</h3>
<form id="Form1" method="post" runat="server">
<asp:DataGrid ID="DG_Persons" AutoGenerateColumns=False Width="99%"
HeaderStyle-BackColor="#ff0000" HeaderStyle-Font-Bold="True" HeaderStyle-ForeColor="#ffffff"
ItemStyle-BackColor=Beige BorderColor="#000000" Runat=server HeaderStyle-HorizontalAlign=Center>
<Columns>
<asp:TemplateColumn HeaderText="姓名">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonName") %>' ID="Label1"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="电子邮件">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonEmail") %>' ID="Label2"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="性别">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonSex") %>' ID="Label3"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="出生日期">
<ItemTemplate>
<asp:Label Runat="server"
Text='<%# DataBinder.Eval(Container.DataItem, "PersonDOB") %>' ID="Label4"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="照片">
<ItemTemplate>
<asp:Image Runat=server ID="Image1" Width="150" Height="125"
ImageUrl='<%# FormatURL(DataBinder.Eval(Container.DataItem, "PersonID")) %>' />
</ItemTemplate>
</asp:TemplateColumn>
</Columns>
</asp:DataGrid>
</form>
</body>
</html>

ReadImage.aspx

<%@ Page Language="vb" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<HTML>
<HEAD>
<script runat=server>
Public Sub Page_Load(sender As Object, e As EventArgs)
Dim strImageID as String = Request.QueryString("id")
Dim myConnection As New SqlConnection("Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;")
Dim myCommand As New SqlCommand("Select PersonImageType, PersonImage from Person Where PersonID=" _
+ strImageID, myConnection)

Try
myConnection.Open()
Dim myDataReader as SqlDataReader
myDataReader = myCommand.ExecuteReader(CommandBehavior.CloseConnection)
Do While (myDataReader.Read())
Response.ContentType = myDataReader.Item("PersonImageType")
Response.BinaryWrite(myDataReader.Item("PersonImage"))
Loop
myConnection.Close()
Catch SQLexc As SqlException
End Try
End Sub
</script>
</HEAD>
<body>
<form runat="server" ID="Form1"></form>
</body>
</HTML>


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