求线程同步高手：经典生产者和消费者如何用VC实现（50），我的程序问题出在什么地方（50）

2004-01-09 02:24:10 210 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

trace (矩阵的迹) 的性质 trace (矩阵的迹) 的性质性质1 tr(Am×nBn×m)=tr(BA)tr(Am×nBn×m)=tr(BA)\mathrm {tr} ( A_{m \times n}B_{n \times m} ) = \mathrm {tr} (BA) 证明 tr(AB)tr(AB)\mathrm {tr} ( A B) =∑i=1m(AB)ii=∑i=1m(AB)ii= \sum \... 阅读详情

我编了段代码不知怎么老出错
开始我吧互斥和信号量的创建都写到共享资源里了不行
后来又写到线程里利用了相同名称错误照旧
逻辑上完全按照操作系统课本的模式
还是出错郁闷郁闷郁闷郁闷郁闷郁闷郁闷郁闷郁闷郁闷……
int CConsumerThread::Run()
{
CP_CDlg *pDlg;
pDlg=(CP_CDlg*)this->m_pParent;
char*pBuf;
pBuf=this->m_Data;

CSemaphore* m_pSemaphoreEmpty;
CSemaphore* m_pSemaphoreFull;
CMutex *m_pMutex;

m_pSemaphoreFull =new CSemaphore(1,1,"SemaphoreFull");
m_pSemaphoreEmpty =new CSemaphore(0,1,"SemaphoreEmpty");
m_pMutex =new CMutex(false,"PC_Mutex");

CSingleLock mutexLock(m_pMutex),FullLock(m_pSemaphoreFull ),EmptyLock(m_pSemaphoreEmpty);

for(int i=0;i<CSM_BUF_COUNT;i+=10)
{
FullLock.Lock();
mutexLock.Lock();
sprintf(pBuf,pDlg->m_sBuf);
mutexLock.Unlock();
pBuf+=10;
m_Data[1000]=0;
mutexLock.Lock();
sprintf(pDlg->m_sBufCSM.GetBuffer(0),&m_Data[i]);
mutexLock.Unlock();
EmptyLock.Unlock();
}
return CWinThread::Run();
}

int CProducerThread::Run()
{
// TODO: Add your specialized code here and/or call the base class
CSemaphore* m_pSemaphoreEmpty;
CSemaphore* m_pSemaphoreFull;
CMutex *m_pMutex;
m_pSemaphoreFull =new CSemaphore(1,1,"SemaphoreFull");
m_pSemaphoreEmpty =new CSemaphore(0,1,"SemaphoreEmpty");
m_pMutex =new CMutex(false,"PC_Mutex");//
CP_CDlg *pDlg;
pDlg=(CP_CDlg*)m_pParentDlg;
CSingleLock mutexLock(m_pMutex),FullLock(m_pSemaphoreFull ),EmptyLock(m_pSemaphoreEmpty );

for(int i=0;i<100000;i++)
{
EmptyLock.Lock();
mutexLock.Lock();
pDlg->m_sBuf.Format("%0.10d",i);
mutexLock.Unlock();
FullLock.Unlock();
pDlg->UpdateData(false);
}
return CWinThread::Run();
}
Debug错误提示 mtex.cpp line 107
如果去掉信号量，只互斥没问题。
看起来是信号量使用的错误。

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