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怎样计算时间差！！！
我想计算两个时间差：如2004-02-23 20:23 2004-02-24 00:23
如何计算？？
如何计算？？
...全文
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SafeF8 2004-07-30
严重同意二楼!
ryuginka 2004-07-30
都说了,我看看
helanshan 2004-07-30
直接进行计算就可以
Private Sub Command1_Click()
Dim d1 As Date
Dim d2 As Date
d1 = "2004-01-23 20:23"
d2 = "2004-02-24 00:23 "
Print (d2 - d1) * 24 ’乘24返回小时，不乘24返回天数
End Sub
Private Sub Command1_Click()
Dim d1 As Date
Dim d2 As Date
d1 = "2004-01-23 20:23"
d2 = "2004-02-24 00:23 "
Print (d2 - d1) * 24 ’乘24返回小时，不乘24返回天数
End Sub
我和我的蓝天白云 2004-07-30
function GetDoTime(Time1, Time2)
Dim stime
If Time1 > Time2 Then
stime = Time1
Time1 = Time2
Time2 = stime
End If
secondvalue = DateDiff("s", Time1, Time2)
dayvalue = DateDiff("d", Time1, Time2)
hourvalue = Fix((secondvalue - dayvalue * 24 * 3600) / 3600)
If hourvalue < 0 Then dayvalue = dayvalue - 1: hourvalue = 24 + hourvalue
minitevalue = Fix((secondvalue - dayvalue * 24 * 3600 - hourvalue * 3600) / 60)
If minitevalue < 0 Then hourvalue = hourvalue - 1: minitevalue = 60 + minitevalue
secvalue = secondvalue - dayvalue * 24 * 3600 - hourvalue * 3600 - minitevalue * 60
If secvalue < 0 Then minitevalue = minitevalue - 1: secvalue = 60 + secvalue
GetDoTime=dayvalue & "天" & hourvalue & "小时" & minitevalue & "分" & secvalue & "秒"
End function
Dim stime
If Time1 > Time2 Then
stime = Time1
Time1 = Time2
Time2 = stime
End If
secondvalue = DateDiff("s", Time1, Time2)
dayvalue = DateDiff("d", Time1, Time2)
hourvalue = Fix((secondvalue - dayvalue * 24 * 3600) / 3600)
If hourvalue < 0 Then dayvalue = dayvalue - 1: hourvalue = 24 + hourvalue
minitevalue = Fix((secondvalue - dayvalue * 24 * 3600 - hourvalue * 3600) / 60)
If minitevalue < 0 Then hourvalue = hourvalue - 1: minitevalue = 60 + minitevalue
secvalue = secondvalue - dayvalue * 24 * 3600 - hourvalue * 3600 - minitevalue * 60
If secvalue < 0 Then minitevalue = minitevalue - 1: secvalue = 60 + secvalue
GetDoTime=dayvalue & "天" & hourvalue & "小时" & minitevalue & "分" & secvalue & "秒"
End function
