如何得到BCD码

cs_lyl 2004-03-24 09:16:09

我有个值int i=771
转换成16进制是0303,
我想得到字符型的"0303",
请教如何实现！！！！

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cs_lyl 2004-03-24

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多谢

thp 2004-03-24

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补上压缩BCD码：
AnsiString ZipBcdToStr(const char bcd)
{
char l,r;
l = (bcd >> 4) & 0x0F;
r = bcd & 0x0F;
return IntToStr(l) + IntToStr(r);
}

fjye 2004-03-24

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昏，BCB可以用IntToHex的啊，我自己都昏了
你直接用IntToHex就可以了
AnsiString b=IntToHex(771,4);

fjye 2004-03-24

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不好意思，写错了，我另写一个，上面是是转ASII码的

fjye 2004-03-24

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AnsiString BCD_to_AnsiString(char * P_BCD, int length)
{
//TODO: Add your source code here
AnsiString returnstring = "";
char high_char,low_char,temp;
for(int i=0;i<length;i++)
{
temp = *P_BCD++;
high_char = (temp&0xf0)>>4;
low_char = temp&0x0f;
if ((high_char>=0x00)&&(high_char<=0x09))
high_char+=0x30;
if ((high_char>=0x0A)&&(high_char<=0x0F))
high_char+=0x37;

if ((low_char>=0x00)&&(low_char<=0x09))
low_char+=0x30;
if ((low_char>=0x0A)&&(low_char<=0x0F))
low_char+=0x37;

returnstring += AnsiString(high_char);
returnstring += AnsiString(low_char);
}
return returnstring;
}
int i=177;
AnsiString a=IntToStr(i);
AnsiString b=BCD_to_AnsiString(a.c_str(),a.Length());