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看看：上传图片名称总是无法写入数据库，什么地方错了？新手问题，立即给分！

Lengjian 2004-04-06 10:46:45

<%@ codepage ="936" %>
<%id=request("id")%>

<%
set rs=server.createobject("ADODB.recordset")
rs.Open "SELECT * FROM qyml Where cimg is null",conn,1,3
rs.addnew
nowtime=now()
sj=cstr(year(nowtime))+"-"+right("0"+cstr(month(nowtime)),2)+"-"+right("0"+cstr(day(nowtime)),2)
%>

<%dim upload,file,formName,formPath,iCount
set upload=new upload_F ''建立上传对象
'--------将日期转化成文件名--------
function MakedownName()
dim fname
fname = now()
fname = replace(fname,"-","")
fname = replace(fname," ","")
fname = replace(fname,":","")
fname = replace(fname,"PM","")
fname = replace(fname,"AM","")
fname = replace(fname,"上午","")
fname = replace(fname,"下午","")
fname = int(fname) + int((10-1+1)*Rnd + 1)
MakedownName=fname
end function
formPath="mvp/"
iCount=0
for each formName in upload.file ''列出所有上传了的文件
set file=upload.file(formName) ''生成一个文件对象
if file.FileSize>0 then ''如果 FileSize > 0 说明有文件数据
newname=MakedownName()&"."&mid(file.FileName,InStrRev(file.FileName, ".")+1)
file.SaveAs Server.mappath(formPath&newname) ''保存文件
iCount=iCount+1
else
response.write "未找到文件 <A HREF=javascript:history.back(1)>返回</A>"
response.end
end if
next
set rs=server.CreateObject("ADODB.RecordSet")
rs.open "select * from qyml where id="&id,conn,1,3
rs.addnew
rs("cimg")=formPath&newname
rs.update
rs.close
set rs=nothing
conn.close
set upload=nothing ''删除此对象
%>
<link rel="stylesheet" type="text/css" href="../style.css">
<body bgcolor="#FFFFFF" marginheight=0 marginwidth=0 leftmargin=0>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<BODY>
<div align="center">
<center>
<TABLE border=0 bordercolorlight='#FFFFFF' bordercolordark=#FFFFFF cellspacing=3 cellpadding=3 width="319" style="border-collapse: collapse" bordercolor="#111111" height="141">
<TR>
<TD width="315" bgcolor="#FBFDFF" height="132">
<p align="center">文件已经成功上传，是否继续添加……<BR>
<%
response.write file.FilePath&file.FileName&" ("&cint(file.FileSize/1024)&"K) 上传成功!<br>"
%> </p>
<P><P align="center"><a href="cimg_add.asp">继续添加</a> <A HREF="javascript:window.close()">关闭窗口</A></TD>
</TR>
</table>
</center>
</div>
<%
set file=nothing
set upload=nothing ''删除此对象
%>

...全文

8 条回复

切换为时间正序

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dafei0320 2004-04-08

rs.Open "SELECT * FROM qyml Where ----",conn,1,3
rs.addnew

rs.open "select * from qyml where id="&id,conn,1,3
rs.addnew

rs.close

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yxfangela 2004-04-07

set rs=server.createobject("ADODB.recordset")
rs.Open "SELECT * FROM qyml Where cimg is null",conn,1,3
rs.addnew
nowtime=now()
sj=cstr(year(nowtime))+"-"+right("0"+cstr(month(nowtime)),2)+"-"+right("0"+cstr(day(nowtime)),2)
后面写上rs.update
rs.close
set rs=nothing

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pizixt 2004-04-07

<%id=request("id")%> 这个id是怎么生成的？

下面这两句在前面有什么作用？而且没有rs.close，不报错？？
rs.Open "SELECT * FROM qyml Where cimg is null",conn,1,3
rs.addnew

rs.open "select * from qyml where id="&id,conn,1,3
rs.addnew -------？

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Jacklyluo 2004-04-07

用insert 语句
mySQL="insert into qyml (cimg) values('"& file.FileName &"')"
con.execute mySQL

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Lengjian 2004-04-07

文件传上去了，可是数据库字段里没有插入数据！

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tlane 2004-04-07

<%id=request("id")%> 这个id是如何传递过来的?用户id,还是相册文件夹id?
如果是新增的话
把
rs.open "select * from qyml where id="&id,conn,1,3
rs.addnew
改为
rs.Open "select* from qyml",conn,1,3
rs.addnew
去掉上面的那段
set rs=server.createobject("ADODB.recordset")
rs.Open "SELECT * FROM qyml Where cimg is null",conn,1,3
rs.addnew
要不然怎么可能通过呢，会报错的...

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