如何读取XML文件的内容?
我的XML文件的内容如下:
<?xml version="1.0" encoding="utf-8"?>
<root>
<backfile>
<id>1</id>
<title>db_web_20040409_2109.dll</title>
<createtime>2004-04-09</createtime>
<linkname>D:/BackUp/DataBase/db_web_20040409_2109.dll</linkname>
<dosomething>Restore</dosomething>
</backfile>
<backfile>
<id>2</id>
<title>db_web_20040409_2116.dat</title>
<createtime>2004-04-09</createtime>
<linkname>D:/BackUp/DataBase/db_web_20040409_2116.dat</linkname>
<dosomething>Restore</dosomething>
</backfile>
<backfile>
<id>3</id>
<title>db_web_20040409_2116.dat</title>
<createtime>2004-04-09</createtime>
<linkname>D:/BackUp/DataBase/db_web_20040409_2116.dat</linkname>
<dosomething>Restore</dosomething>
</backfile>
<backfile>
<id>4</id>
<title>db_web_20040410_1459.dll</title>
<createtime>2004-04-10</createtime>
<linkname>D:/BackUp/DataBase/db_web_20040410_1459.dll</linkname>
<dosomething>Restore</dosomething>
</backfile>
<backfile>
<id>5</id>
<title>db_web_20040410_1500.bak</title>
<createtime>2004-04-10</createtime>
<linkname>D:/BackUp/DataBase/db_web_20040410_1500.bak</linkname>
<dosomething>Restore</dosomething>
</backfile>
<backfile>
<id>6</id>
<title>db_web_20040410_1501.dat</title>
<createtime>2004-04-10</createtime>
<linkname>D:/BackUp/DataBase/db_web_20040410_1501.dat</linkname>
<dosomething>Restore</dosomething>
</backfile>
</root>
如何倒序读取linkname和title
然后ListItem li=new ListItem(title,linkname)
将li加入一listbox!!!
我不会xml的操作,大家帮帮忙?