求救！！！

[wangyi_1000]

MyList::MyList(char* t_name,char* t_ser)
{
ZeroMemory(name,100);
ZeroMemory(ser_name,100);
memcpy(name,t_name,sizeof(t_name));
memcpy(ser_name,t_ser,sizeof(t_ser));
}
name与ser_name为char[100];
为何memcpy后没有拷贝到

[subtop]

sizeof()
你要明白它会执行什么?
传给它指针，它始终返回4——指针变量的字节数。
如果不好确定要拷贝的字符字节数，并且待拷贝字符数组是以'\0'结束的话，建议你使用strcpy();
当然，你也可以指定一个最大字节数，只要不大过t_ser,t_name的有效地址长度。


附：

sizeof Operator
sizeof expression

The sizeof keyword gives the amount of storage, in bytes, associated with a variable or a type (including aggregate types). This keyword returns a value of type size_t.

The expression is either an identifier or a type-cast expression (a type specifier enclosed in parentheses).

When applied to a structure type or variable, sizeof returns the actual size, which may include padding bytes inserted for alignment. When applied to a statically dimensioned array, sizeof returns the size of the entire array. The sizeof operator cannot return the size of dynamically allocated arrays or external arrays.

[subtop]

给你一个例子：

void pointer_size(char *s)
{
cout << sizeof(s) << endl;
}
char ch[20];

sizeof(ch);//此处是20
pointer_size(ch);//输出为4

[cngdzhang]

这是因为sizeof的问题

MyList::MyList(char* t_name,char* t_ser)
{
ZeroMemory(name,100);
ZeroMemory(ser_name,100);
memcpy(name,t_name,sizeof(t_name)); //这里的sizeof(t_name)结果是4
memcpy(ser_name,t_ser,sizeof(t_ser));//这里的sizeof(t_ser)结果也是4
}

作形参的时候,只要是指针,sizeof就是4

用strcpy吧
或者
传入多两个参数
MyList::MyList(char* t_name,char* t_ser,int namesize,int sersize)
{
ZeroMemory(name,100);
ZeroMemory(ser_name,100);
memcpy(name,t_name,namesize);
memcpy(ser_name,t_ser,sersize);
}

[cmx98]

同意楼上2位的

[kuangjingbo]

同意楼上各位的

[zhjie374]

对,sizeof()大小没有搞对!