晚饭没吃用我最后一口力气问大虾一个问题

[OdellaChen]

insert into total (trade_co,A,B,C,num) values(@trade_co,@a,@b,@c,1)

哪里错了

[zheninchangjiang]

没有地方错呀,前提是定义了那几个变量

[internetcsdn]

支持一楼

[internetcsdn]

同意楼主,未吃饭

[DigJim]

看看你的表名和字段名有沒有大小寫搞錯！！

[8992026]

哪里错了？
数据类型不一致是很可能的

[8992026]

楼上的楼上：哪填贴出小宝宝的照片？？？

[OdellaChen]

不弄了，我要牺牲在回家的路上了

[zheninchangjiang]

你该看一下数据库的排序规则,
select * from syscolumns where name in ('A','B','C') --where id=object_id('total')
select * from syscolumns where name in ('a','b','c') --where id=object_id('total')
看看是不是有结果

[zjcxc]

将错误提示帖出来,一看便知,费事大家猜

[OdellaChen]

alter proc s6
AS
declare @trade_co char(10),
@a char(20),
@b char(20),
@c char(20),
@k int
select @k=0
declare hh_cursor cursor for
select trade_co,
A,
B,
C
from IM_ENTRY_HEAD
where datediff(day,D_Date,getdate())=0 And LEFT(PROCESS_MARK,2)<>'1B'

open hh_cursor

fetch next from hh_cursor
into @trade_co,
@a,
@b,
@c

while @@FETCH_STATUS = 0

begin

select @k=@k+1
if exists(select trade_co where trade_co=@trade_co and A=@a and B=@b and C=@c)
begin
update total set num=num+1 where trade_co=@trade_co and A=@a and B=@b and C=@c
update total set allnum=allnum+1 where trade_co=@trade_co and A=@a and B=@b and C=@c
update total set p=num/allnum
end
else
begin
insert into total (trade_co,A,B,C,num) values(@trade_co,@a,@b,@c,1)
update total set allnum=(select distinct allnum from total where trade_co=@trade_co)
update total set p=num/allnum
end
fetch next from hh_cursor into
@trade_co,
@a,
@b,
@c

end

close hh_cursor
deallocate hh_cursor

return @k

go


exec s6

select * from total order by trade_co

[OdellaChen]

up~