16,471
社区成员
发帖
与我相关
我的任务
分享新手上路：请问C++或MFC中如何生成一定范围内的随机数？
请问C++或MFC中如何生成一定范围内的随机数？
例如我想生成1-100之间的一个随机数，如何实现啊？
谢谢！
例如我想生成1-100之间的一个随机数，如何实现啊？
谢谢！
...全文
请发表友善的回复…
发表回复
JerryGR 2004-07-04
- 打赏
- 举报
i = MulDiv(rand(),100,RAND_MAX)
sambo 2004-07-04
- 打赏
- 举报
改正： i =rand()%100 +1;
sambo 2004-07-04
- 打赏
- 举报
srand((unsigned)time(NULL));
int i = 0;
i = rand()%100; //i is in [1,100]
int i = 0;
i = rand()%100; //i is in [1,100]
needways 2004-07-04
- 打赏
- 举报
srand( (unsigned)time( NULL ) );
int nValue = rand() % 100 + 1;
int nValue = rand() % 100 + 1;
Kudeet 2004-07-04
- 打赏
- 举报
ＭＳＤＮ的例子
Example
// crt_rand.c
/* This program seeds the random-number generator
* with the time, then displays 10 random integers.
*/
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
int main( void )
{
int i;
/* Seed the random-number generator with current time so that
* the numbers will be different every time we run.
*/
srand( (unsigned)time( NULL ) );
/* Display 10 numbers. */
for( i = 0; i < 10;i++ )
printf( " %6d\n", rand() );
}
Sample Output
19430
28222
9710
12070
7513
9501
1767
26041
11872
4097
Example
// crt_rand.c
/* This program seeds the random-number generator
* with the time, then displays 10 random integers.
*/
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
int main( void )
{
int i;
/* Seed the random-number generator with current time so that
* the numbers will be different every time we run.
*/
srand( (unsigned)time( NULL ) );
/* Display 10 numbers. */
for( i = 0; i < 10;i++ )
printf( " %6d\n", rand() );
}
Sample Output
19430
28222
9710
12070
7513
9501
1767
26041
11872
4097
