重写控件的鼠标响应后ContextMenu无法显示的问题

[broadury]

我写一个PictureBox的MouseMove和MouseLeave事件后，右击鼠标想显示ContextMenu，结果是一闪而过，无法显示。这该如何解决？

[songbird]

代码贴出来看看

[broadury]

PanelIcon是一个继承PictureBox的类，编译成用户控件，在Windows应用程序中调用，并指定了ContextMenu，但是完成鼠标响应的代码后菜单就出不来了：
public class PanelIcon : PictureBox
{
public int index;
public IconPanel iconPanel;
public uint ID;

private Color bckgColor;
private bool mouseEnter;

public int Index
{
get
{
return index;
}
}

public PanelIcon(IconPanel parent, Image image, int index, EventHandler onDoubleClickEvent)
{
this.index=index;
this.iconPanel=parent;
Image=image;
Visible=true;
Location=new Point(iconPanel.outlookBar.Size.Width/2-image.Size.Width/2,
iconPanel.Margin + index*iconPanel.IconSpacing);
Size=image.Size;
DoubleClick+=onDoubleClickEvent;
Tag=this;

MouseEnter+=new EventHandler(OnMouseEnter);
DoubleClick+=new EventHandler(onDoubleClickEvent);
MouseLeave+=new EventHandler(OnMouseLeave);
MouseMove+=new MouseEventHandler(OnMouseMove);
MouseDown+=new MouseEventHandler(OnMouseDown);
MouseUp+=new MouseEventHandler(OnMouseUp);
bckgColor=iconPanel.BackColor;
mouseEnter=false;
}

private void OnMouseMove(object sender, MouseEventArgs args)
{
if ( (args.X < Size.Width-2) &&
(args.Y < Size.Width-2) &&
(!mouseEnter) )
{
BackColor=Color.LightCyan;
BorderStyle=BorderStyle.FixedSingle;
Location=Location-new Size(1, 1);
mouseEnter=true;
}
}

private void OnMouseLeave(object sender, EventArgs e)
{

if (mouseEnter)
{
BackColor=bckgColor;
BorderStyle=BorderStyle.None;
Location=Location+new Size(1, 1);
mouseEnter=false;
}
}

private void OnMouseDown(object sender, MouseEventArgs args)
{
if ( (args.X < Size.Width-2) &&
(args.Y < Size.Width-2) &&
(!mouseEnter) )
{
BackColor=Color.LightCyan;
BorderStyle=BorderStyle.Fixed3D;
Location=Location+new Size(1, 1);
}
}

private void OnMouseUp(object sender, MouseEventArgs args)
{
if ( (args.X < Size.Width-2) &&
(args.Y < Size.Width-2) &&
(!mouseEnter) )
{
BackColor=Color.LightCyan;
BorderStyle=BorderStyle.None;
Location=Location-new Size(1, 1);
}
}

private void OnMouseEnter(object sender, EventArgs e)
{
}

private void OnMouseClick(object sender, EventArgs e)
{
}


}

[lookie]

应该没有问题