安装好tomcat后需不需要配置环境变量
系统2000server+jdk142+tomcat5014
在安装好上面的东西后,开始java的练习,启动tomcat服务器,编写如下的文件
submit.jsp
===================
<%@ page contentType="text/html;charset=gb2312" %>
<html>
<head>
<title>数据库演示</title>
</head>
<body>
<center>
<form method="post" action="deal.jsp" >
请输入用户名:<input type="text" name="username" size="20"><br>
请输入密 码:<input type="password" name="pwd" size="20"><br>
<input type="submit" name="submit" value="提交">
</form>
</center>
</body>
</html>
运行
出现下面的错误
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: Unable to compile class for JSP
No Java compiler was found to compile the generated source for the JSP.
This can usually be solved by copying manually $JAVA_HOME/lib/tools.jar from the JDK
to the common/lib directory of the Tomcat server, followed by a Tomcat restart.
If using an alternate Java compiler, please check its installation and access path.
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:127)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:418)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:461)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:442)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:552)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
note The full stack trace of the root cause is available in the Tomcat logs.
让我把JAVA_HOME/lib/tools.jar 拷贝到响应的目录下
这个是不是没有配置环境变量的原因,如果需要配置环境变量,应当配置那些环境变量,环境变量的值是什么??
谢谢