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shangqiao 2004-07-25
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想一想这种情况:
int ff();
double ff();
现在有代码:
ff();
你能决定他是调用哪一个方法嘛,你都不能,电脑怎么又能!返回值是执行完方法体时才得到的,这时才知道他的类型,但是这是果,怎么能够由果推因呢?逻辑不相符.
不仅仅返回值不行,还有异常也一样,因为异常是返回类型的特殊形式而已,所以也是不能根据它重载的
int ff();
double ff();
现在有代码:
ff();
你能决定他是调用哪一个方法嘛,你都不能,电脑怎么又能!返回值是执行完方法体时才得到的,这时才知道他的类型,但是这是果,怎么能够由果推因呢?逻辑不相符.
不仅仅返回值不行,还有异常也一样,因为异常是返回类型的特殊形式而已,所以也是不能根据它重载的
sboom 2004-07-25
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仅仅只是返回类型不同,并不是重载
Jane000 2004-07-25
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仅仅只是返回类型不同,并不是重载
registered 2004-07-25
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返回类型跟 overload 毫无关系...
umbrella1984 2004-07-25
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重载的条件
必须修改参数列表
可以修改返回类型
仅单独使用返回类型不能辨别是调用哪个方法
必须修改参数列表
可以修改返回类型
仅单独使用返回类型不能辨别是调用哪个方法
gameboy999 2004-07-25
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Overloading
1.Signature has to be different. Just a difference in return type is not enough.
Accessibility may vary freely.
2.Exception list may vary freely.
3.Just the name is reused. Methods are independent methods. Resolved at compile-time based on method signature.
4.Can call each other by providing appropriate argument list.
5.Methods can be static or non-static. Since the methods are independent, it doesn’t matter. But if two methods have the same signature, declaring one as static and another as non-static does not provide a valid overload. It’s a compile time error.
6.There’s no limit on number of overloaded methods a class can have.
1.Signature has to be different. Just a difference in return type is not enough.
Accessibility may vary freely.
2.Exception list may vary freely.
3.Just the name is reused. Methods are independent methods. Resolved at compile-time based on method signature.
4.Can call each other by providing appropriate argument list.
5.Methods can be static or non-static. Since the methods are independent, it doesn’t matter. But if two methods have the same signature, declaring one as static and another as non-static does not provide a valid overload. It’s a compile time error.
6.There’s no limit on number of overloaded methods a class can have.
