aspupload 不能获得文件名
为什么处理时得不到文件名
代码:
Set Upload=Server.createobject("Persits.Upload.1") '创建文件上载组件
Upload.OverwriteFiles = False
Upload.SetMaxSize 33554432, True
Count=Upload.Save(server.mappath("files\archives\")) '将客户端文件保存到WEB服务器端的本地硬盘上
if Err.Number = 8 then
Response.Write "文件超过32兆限制."
elseif Err <> 0 then
Response.Write "发生错误: " & Err.Description
elseif Count < 1 then
'不做处理
end If
title = upload.form("title")
kind = upload.form("kind")
Tfile=upload.form("filepath")
if Tfile <> "" then
Set File = Upload.Files(1)
filename1="/files/archives/"&file.filename
filename0=file.filename
end if
为什么Tfile的值为空,而title,kind可以的到对应的值
提交页的form
<FORM method=post name="form" ENCTYPE="multipart/form-data" action="addarcproess.asp">
filepath对应的
<input type="file" name="filepath" size=50>