如何把一个8位灰度图像读到一个二维数组中？

[cutelocust]

rt

[cutelocust]

还有，如何从数组中显示该图像？

[howtotell]

位图的结构是比较复杂的,里面的数据和头都是以结构体的形式存在的,用一个二位数组表示不是很方便.你要读进内存,可以考虑使用内存映像文件,然后再像操作内存里的指针那样操作是比较可行的办法.
现实位图的方法很多:
#define HIMETRIC_INCH 2540
LPPICTURE gpPicture;
void CMasterView::ShowPicture(CDC *pDC, CString m_strBRoute, int x, int y, int width, int height)
{
HANDLE hFile = CreateFile(m_strBRoute, GENERIC_READ, 0, NULL, OPEN_EXISTING, 0, NULL);
_ASSERTE(INVALID_HANDLE_VALUE != hFile);

// 取得文件大小
DWORD dwFileSize = GetFileSize(hFile, NULL);
_ASSERTE(-1 != dwFileSize);
LPVOID pvData = NULL;
//根据文件大小分配内存
HGLOBAL hGlobal = GlobalAlloc(GMEM_MOVEABLE, dwFileSize);
_ASSERTE(NULL != hGlobal);
pvData = GlobalLock(hGlobal);
_ASSERTE(NULL != pvData);
DWORD dwBytesRead = 0;
//读取文件并存入全局内存
BOOL bRead = ReadFile(hFile, pvData, dwFileSize, &dwBytesRead, NULL);
_ASSERTE(FALSE != bRead);
GlobalUnlock(hGlobal);
CloseHandle(hFile);
LPSTREAM pstm = NULL;
// 通过全局内存创建 IStream* 的指针
HRESULT hr = CreateStreamOnHGlobal(hGlobal, TRUE, &pstm);
_ASSERTE(SUCCEEDED(hr) && pstm);
//通过图形文件创建IPicture 对象
if (gpPicture)
gpPicture->Release();
hr = OleLoadPicture(pstm, dwFileSize, FALSE, IID_IPicture, (LPVOID *)&gpPicture);
_ASSERTE(SUCCEEDED(hr) && gpPicture);
pstm->Release();
HDC hdc;
hdc=pDC->GetSafeHdc();
if (gpPicture)
{
// 取得图片的宽和高
long hmWidth;
long hmHeight;
gpPicture->get_Width(&hmWidth);
gpPicture->get_Height(&hmHeight);
//宽高转换为象素
int nWidth = MulDiv(hmWidth, GetDeviceCaps(hdc, LOGPIXELSX), HIMETRIC_INCH);
int nHeight = MulDiv(hmHeight, GetDeviceCaps(hdc, LOGPIXELSY), HIMETRIC_INCH);
RECT rc;
GetClientRect(&rc);/*取得客户区*/
gpPicture->Render(hdc, x,y, (int)height*hmWidth/hmHeight,height, 0, hmHeight, hmWidth, -hmHeight, &rc);
/*显示图片*/
}
GlobalFree(hGlobal);

}