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我现在要得到20040805这样的日期格式，但如何得到呢？使用response.write (date)输出的2004-8-5的格式，如何得到20040805的格式呢？
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bolm 2004-08-05
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我以前用的是 duxingxue(3321) 的方法，比较简单，用来生成定单号比较实用！
duxingxue 2004-08-05
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忘了加零，：）
datestr=date
findate=year(datestr)&right("0"&month(datestr),2)&right("0"&day(datestr),2)
response.write(replace(findate,"-",""))
datestr=date
findate=year(datestr)&right("0"&month(datestr),2)&right("0"&day(datestr),2)
response.write(replace(findate,"-",""))
duxingxue 2004-08-05
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response.write(replace(date,"-",""))
叮咚叮咚叮叮咚 2004-08-05
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很多这问题呢
thedate=cdate("2004-8-5")
fdate=year(thedate)&right("0"&month(thedate),2)&right("0"&day(thedate),2)
thedate=cdate("2004-8-5")
fdate=year(thedate)&right("0"&month(thedate),2)&right("0"&day(thedate),2)
jiangrod 2004-08-05
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谢谢，结贴，给上面的仁兄加分
xiaobird1 2004-08-05
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strTemp = Split( date(), "-" )
strNewDate = strTemp(0)
If Len( strTemp(1) ) = 1 Then
strNewDate = strNewDate & "0" & strTemp(1)
End If
If Len( strTemp(2) ) = 1 Then
strNewDate = strNewDate & "0" & strTemp(2)
End If
Response.write strNewDate
strNewDate = strTemp(0)
If Len( strTemp(1) ) = 1 Then
strNewDate = strNewDate & "0" & strTemp(1)
End If
If Len( strTemp(2) ) = 1 Then
strNewDate = strNewDate & "0" & strTemp(2)
End If
Response.write strNewDate
顺子 2004-08-05
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ddate=cdate(date1)
sdate1=year(ddate)&"-"& month(ddate)&"-"&day(ddate)
sdate1=year(ddate)&"-"& month(ddate)&"-"&day(ddate)
