急，高分求添几行小代码（StringTokenizer类的吧）！

[zhgc2003]

package u;

public class U
{
public U()
{
}
public static void main(String[] args)
{
U u1 = new U();
String str = "abcdefg/username=$username&userpass=$userpass&usersex=1";
String[] strs = u1.parse(str);
String temp = "";
for (int i = 0; i < strs.length; i++) {
System.out.println(strs[i]);
temp += strs[i];
}
System.out.println(temp);
}

private String[] parse(String str)
{
return null;
}
}
要求效果：
输入:
abcdefg/username=$username&userpass=$userpass&usersex=1

输出:
abcdefg/username=
$username
&userpass=
$userpass
&usersex=1
数组内所有元素相加，还能得到：abcdefg/username=$username&userpass=$userpass&usersex=1

帮忙添一下代码，万分感谢！

[Acylas]

private static String[] parse(String str) {
java.util.StringTokenizer stk = new java.util.StringTokenizer(str, "&");
String[] strs = new String[stk.countTokens() * 2];
int i=0;
String strTmp;
while (stk.hasMoreTokens()) {
strTmp = stk.nextToken();
strs[i] = strTmp.substring(0, strTmp.indexOf("=") + 1);
i++;
strs[i] = strTmp.substring(strTmp.indexOf("=") + 1);
i++;
}
return strs;
}

[fim]

String str = "abcdefg/username=$username&userpass=$userpass&usersex=1";
StringTokenizer st = new StringTokenizer(str,"=");
while (st.hasMoreTokens()) {
System.out.println(st.nextToken());
}

[zhgc2003]

请加注视，谢谢喽

[mingjava]

用StringTokenizer先按照$来分出String[]来 然后再把含有&的用StringTokernizer再分一次 最后返回一个String[]

[zhgc2003]

显示的结果是：
abcdefg/username=
$username
userpass=
$userpass
usersex=
1
啊

[zhgc2003]

stk.countTokens() * 2是什么意思？

[zcwhgj]

这里是j2me版块啊.j2me没有这个类:StringTokenizer,呵呵.

[zhgc2003]

要求效果：
输入:
abcdefg/username=$username&userpass=$userpass&usersex=1

输出:
abcdefg/username=
$username
&userpass=
$userpass
&usersex=1

[zhgc2003]

难道非要用StringTokenizer来做吗？

[Acylas]

楼主真是懒不动下脑，那你怎么提供能力啊？
private static String[] parse(String str) {
java.util.StringTokenizer stk1 = new java.util.StringTokenizer(str, "&");
java.util.StringTokenizer stk2;
java.util.ArrayList list = new java.util.ArrayList();
while (stk1.hasMoreTokens()) {
stk2 = new java.util.StringTokenizer(stk1.nextToken(), "$");
while (stk2.hasMoreTokens())
list.add(stk2.nextToken());
}
String[] strs = new String[list.size()];
list.toArray(strs);
return strs;
}

[zhgc2003]

package u;

import java.util.*;

public class U
{
public U()
{
}

public static void main(String[] args)
{
U u1 = new U();
String str = "abcdefg/username=$username&userpass=$userpass&usersex=1";
String ss = "";
String[] strs = u1.parse(str);
String temp = "";

for (int i = 0; i < strs.length; i++)
{
ss = strs[i];
String[] sts = u1.parseB(ss);
for (int j = 0; j < sts.length; j++)
{
if (sts[j] == null || sts[j].equals("")) {
System.out.print("空");
}
System.out.println(sts[j]);
}
temp += strs[i];
}
System.out.println("原字符串: " + temp);
}

private String[] parse(String str)
{
StringTokenizer stk = new StringTokenizer(str, "$");
String[] strsB = new String[stk.countTokens() * 2];

int j = 0;
String strTmp;
while (stk.hasMoreTokens())
{
strTmp = stk.nextToken();
if (j == 0)
{
strsB[j] = strTmp.substring(0, strTmp.indexOf("$") + 1);
j++;
strsB[j] = strTmp.substring(strTmp.indexOf("$") + 1);
j++;
}
else
{
strsB[j] = strTmp.substring(0, strTmp.indexOf("$") + 1);
j++;
strsB[j] = "$" + strTmp.substring(strTmp.indexOf("$") + 1);
j++;
}
}
return strsB;
}

private String[] parseB(String ss)
{
StringTokenizer stk = new StringTokenizer(ss, "&");
String[] strsB = new String[stk.countTokens() * 2];

int j = 0;
String strTmp;
while (stk.hasMoreTokens())
{
strTmp = stk.nextToken();
if (j == 0)
{
strsB[j] = strTmp.substring(0, strTmp.indexOf("&") + 1);
j++;
strsB[j] = strTmp.substring(strTmp.indexOf("&") + 1);
j++;
}
else
{
strsB[j] = strTmp.substring(0, strTmp.indexOf("&") + 1);
j++;
strsB[j] = "&" + strTmp.substring(strTmp.indexOf("&") + 1);
j++;
}
}
return strsB;
}

}
显示结果：
空

abcdefg/username=

空

$username

空

&userpass=

空

$userpass

空

&usersex=1

原字符串: abcdefg/username=$username&userpass=$userpass&usersex=1

为什么多了一倍为空的。。。。啊？？？

[zhgc2003]

to: Acylas(Acylas)
您的方法可以，但是分隔符显示成这个样子才行啊～
abcdefg/username=
$username
&userpass=
$userpass
&usersex=1

不显示分隔符字符串少东西了，用true显示成下面这个样子，郁闷啊！
abcdefg/username=

$

username

&

userpass=

$

userpass

&

usersex=1

abcdefg/username=$username&userpass=$userpass&usersex=1

[zhgc2003]

问题解决，代码共享：
package u;

import java.util.*;

public class U
{
public U()
{
}

public static void main(String[] args)
{
U u1 = new U();
String str = "abcdefg/username=$username&userpass=$userpass&usersex=1";
String[] strs = u1.parse(str);
String temp = "";
String str2 = "";

for (int i = 0; i < strs.length; i++)
{
str2 = strs[i];
String[] sts = u1.parseB(str2);

for (int j = 0; j < sts.length; j++)
{
System.out.println(sts[j]);
}

temp += strs[i];
}
System.out.println("原字符串的和:" + temp);
}

private String[] parse(String str)
{
StringTokenizer stk = null;
try
{
stk = new StringTokenizer(str, "$");
}
catch (Exception ex)
{
ex.printStackTrace();
}
ArrayList list = new ArrayList();
//添加第一个值
list.add(stk.nextToken());
//从第二个值开始累加
while (stk.hasMoreTokens())
{
list.add("$" + stk.nextToken());
}
String[] strs = new String[list.size()];
list.toArray(strs);
return strs;
}

private String[] parseB(String str)
{
StringTokenizer stk = null;
try
{
stk = new StringTokenizer(str, "&");
}
catch (Exception ex)
{
ex.printStackTrace();
}
ArrayList list = new ArrayList();
//添加第一个值
list.add(stk.nextToken());
//从第二个值开始累加
while (stk.hasMoreTokens())
{
list.add("&" + stk.nextToken());
}
String[] strs = new String[list.size()];
list.toArray(strs);
return strs;
}

}

[debug148]

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