求正则表达式,字符串在另一字符串出现次数.

[xiays]

求一个字符串在另一个字符串中的个数,由于效率原因不希望使用循环来遍历长的字符串,所以求最高效的算法.

[eTopFancy]

思路的问题，还是思归No 1

[xiays]

谢谢,思归大侠

[saucer]

you don't need to use regular expressions, and there is no good way with regular expressions, but try

string s = "一个字符串";
string s2 = "另一个字符串";
int n = 0;
s = s.ToLower();
s2 = s2.ToLower();
int i = 0;
while ((i=s2.IndexOf(s, i)) >=0)
{
n++;
i += s1.Length;
}

[simonllf]

MARK

[saucer]

sorry, change

i += s1.Length;
==>
i += s.Length;

or if you insist

using System.Text.RegularExpressions;

string s = @"a\w";
string s2 = @"defa\wdfdfsdfa\wddfdsaw";

Regex re = new Regex(Regex.Escape(s), RegexOptions.IgnoreCase|RegexOptions.Singleline);
MatchCollection mc = re.Matches(s2);
Console.WriteLine(mc.Count);

[jimh]

saucer(思归/MVP)，写得好

[siugwan]

gz

[rgwfeng2]

mark