如何有JS 获取由Web Service返回的xlm中的项目
我已经用JS调用Web Service 但由于我的Web Service返回一个数据集如下:
<?xml version="1.0" encoding="utf-8"?>
<DataSet xmlns="http://tempuri.org/">
<xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:Locale="zh-CN">
<xs:complexType>
<xs:choice maxOccurs="unbounded">
<xs:element name="aaa">
<xs:complexType>
<xs:sequence>
<xs:element name="ROOM_TYPE_ID" type="xs:string" minOccurs="0" />
<xs:element name="ROOM_TYPE" type="xs:string" minOccurs="0" />
<xs:element name="DESCRIPTION" type="xs:string" minOccurs="0" />
<xs:element name="BED_COUNT" type="xs:decimal" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<NewDataSet xmlns="">
<aaa diffgr:id="aaa1" msdata:rowOrder="0">
<ROOM_TYPE_ID>S</ROOM_TYPE_ID>
<ROOM_TYPE>单人间</ROOM_TYPE>
<BED_COUNT>1</BED_COUNT>
</aaa>
<aaa diffgr:id="aaa2" msdata:rowOrder="1">
<ROOM_TYPE_ID>D</ROOM_TYPE_ID>
<ROOM_TYPE>标准间</ROOM_TYPE>
<BED_COUNT>2</BED_COUNT>
</aaa>
<aaa diffgr:id="aaa3" msdata:rowOrder="2">
<ROOM_TYPE_ID>B</ROOM_TYPE_ID>
<ROOM_TYPE>商务标间</ROOM_TYPE>
<BED_COUNT>2</BED_COUNT>
</aaa>
<aaa diffgr:id="aaa4" msdata:rowOrder="3">
<ROOM_TYPE_ID>F</ROOM_TYPE_ID>
<ROOM_TYPE>套房</ROOM_TYPE>
<BED_COUNT>2</BED_COUNT>
</aaa>
<aaa diffgr:id="aaa5" msdata:rowOrder="4">
<ROOM_TYPE_ID>L</ROOM_TYPE_ID>
<ROOM_TYPE>豪华标间</ROOM_TYPE>
<BED_COUNT>2</BED_COUNT>
</aaa>
<aaa diffgr:id="aaa6" msdata:rowOrder="5">
<ROOM_TYPE_ID>C</ROOM_TYPE_ID>
<ROOM_TYPE>夫妻间</ROOM_TYPE>
<BED_COUNT>2</BED_COUNT>
</aaa>
<aaa diffgr:id="aaa7" msdata:rowOrder="6">
<ROOM_TYPE_ID>0</ROOM_TYPE_ID>
<BED_COUNT>2</BED_COUNT>
</aaa>
</NewDataSet>
</diffgr:diffgram>
</DataSet>
我如何才能获得其中的单项数据?