函数中参数的传递问题????
<script>
function openbigpic(names)
{
if (document.all) document.all.names.style.visibility='visible' ;
}
</script>
函数调用:
<div id="bigpic" onmouseenter="openbigpic('bigpic')" style="Z-INDEX: 2; LEFT: 0px; VISIBILITY: hidden; POSITION: absolute; TOP: 0px" >
会提示document.all.names.style为空或不是对象的错误。好象参数bigpic都传递不了,为什么??请问要如何修改??????