用struts，form提交到一个action，报下面错误，大侠们快来看看，急死了；高分相送！！！

[henanhorse]

19:57:46,703 DEBUG [RequestProcessor] Looking for Action instance for class
com.*.*.MsmContentAction
19:57:46,703 DEBUG [RequestProcessor] Returning existing Action instance
javax.servlet.ServletException: Can't find Tile context for com.*.*.MsmContentAction'. TilesAction subclasses must be called from a Tile

配置文件应该是对的，换成别的action是可以的

[popufig]

你给的信息也太少了点吧，比如说你的MsmContentAction是什么.......

[feng8208]

你用到TILES了吗

[cold_blooded]

是不是MsmContentAction 实现TilesAction 的方法名写错了。

[henanhorse]

MsmContentAction 定义：

package com.*;
public class MsmContentAction extends TilesAction {
public ActionForward excute(ActionMapping actionMapping,
ActionForm actionForm,
HttpServletRequest request,
HttpServletResponse response) throws
Exception {
}
}


配置文件：

<action type="com.*.QryMsmContentAction" path="/sm/qryMsmContentAction">
<forward name="success" path="/sm/qrymsmcontent.jsp" />
</action>

jsp中form的action设置为：action="<%=request.getContextPath()%>/sm/msmContentAction.do"

提交时，报上面的错误

可以看到已经从配置文件中找到 "com.*.QryMsmContentAction“，但在生成实例或者调用时出错了

[henanhorse]

如果方法写错了，应该编译不过的，但是我已经打成war包，发布了

[stonecsdn]

重新启动服务试试

[henanhorse]

晕死了，对不起大家了

是方法名写错了

public ActionForward ex e cute(ActionMapping actionMapping,
ActionForm actionForm,
HttpServletRequest request,
HttpServletResponse response) throws
Exception {

少一个e

等改完程序给分

谢谢