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分享XMLHTTP不能发送自定义HTTP_REFERER信息吗？
还是我写的不对？
<script language="JavaScript">
var x = new ActiveXObject("Microsoft.XMLHTTP");
x.open("GET","http://local/aaa.php",false);
x.setRequestHeader("HTTP_REFERER","http://www.test.com");
x.send();
alert(x.responseText);
</script>
============
aaa.php:
<?php
print $_SERVER['HTTP_REFERER'];
?>
<script language="JavaScript">
var x = new ActiveXObject("Microsoft.XMLHTTP");
x.open("GET","http://local/aaa.php",false);
x.setRequestHeader("HTTP_REFERER","http://www.test.com");
x.send();
alert(x.responseText);
</script>
============
aaa.php:
<?php
print $_SERVER['HTTP_REFERER'];
?>
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