67,538
社区成员
发帖
与我相关
我的任务
分享xslt高手帮忙.
<?xml version="1.0" encoding="gb2312" ?>
<?xml-stylesheet type="text/xsl" href="list.xsl" ?>
<list>
<people>
<name>111</name>
</people>
<people>
<name>222</name>
</people>
<people>
<name>333</name>
</people>
<people>
<name>444</name>
</people>
<people>
<name>555</name>
</people>
<people>
<name>666</name>
</people>
<people>
<name>777</name>
</people>
<people>
<name>888</name>
</people>
<people>
<name>999</name>
</people>
<people>
<name>000</name>
</people>
</list>
<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/" >
<html>
<head>
<title>title</title>
<script language="javaScript">
function showMessage( arg )
{
alert( arg.name );
}
</script>
</head>
<body>
<table width="100%" >
<xsl:for-each select="list/people">
<td align="center" valign="top" style='cursor:hand;' onclick="showMessage( this )" >
<xsl:attribute name="name"><xsl:value-of select="name"/></xsl:attribute>
<xsl:value-of select="name"/>
</td>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
如何输出到第5个people时换行输出.
<?xml-stylesheet type="text/xsl" href="list.xsl" ?>
<list>
<people>
<name>111</name>
</people>
<people>
<name>222</name>
</people>
<people>
<name>333</name>
</people>
<people>
<name>444</name>
</people>
<people>
<name>555</name>
</people>
<people>
<name>666</name>
</people>
<people>
<name>777</name>
</people>
<people>
<name>888</name>
</people>
<people>
<name>999</name>
</people>
<people>
<name>000</name>
</people>
</list>
<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/" >
<html>
<head>
<title>title</title>
<script language="javaScript">
function showMessage( arg )
{
alert( arg.name );
}
</script>
</head>
<body>
<table width="100%" >
<xsl:for-each select="list/people">
<td align="center" valign="top" style='cursor:hand;' onclick="showMessage( this )" >
<xsl:attribute name="name"><xsl:value-of select="name"/></xsl:attribute>
<xsl:value-of select="name"/>
</td>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
如何输出到第5个people时换行输出.
...全文
请发表友善的回复…
发表回复
vcvj 2004-10-28
- 打赏
- 举报
<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/" >
<html>
<head>
<title>title</title>
<script language="javaScript">
function showMessage( arg )
{
alert( arg.name );
}
</script>
</head>
<body>
<xsl:for-each select="list/people">
<a style='cursor:hand;' onclick="showMessage( this )" >
<xsl:attribute name="name"><xsl:value-of select="name"/></xsl:attribute>
<xsl:value-of select="name"/>
</a>
<xsl:if test="position()=5"><br/></xsl:if>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/" >
<html>
<head>
<title>title</title>
<script language="javaScript">
function showMessage( arg )
{
alert( arg.name );
}
</script>
</head>
<body>
<xsl:for-each select="list/people">
<a style='cursor:hand;' onclick="showMessage( this )" >
<xsl:attribute name="name"><xsl:value-of select="name"/></xsl:attribute>
<xsl:value-of select="name"/>
</a>
<xsl:if test="position()=5"><br/></xsl:if>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
zcjl 2004-10-28
- 打赏
- 举报
<xsl:for-each select="list/people">
<xsl:if test="position() mod 5 = 1">
<xsl:text disable-output-escaping="yes"><tr></xsl:text>
</xsl:if>
<td align="center" valign="top" style='cursor:hand;' onclick="showMessage( this )" >
<xsl:attribute name="name"><xsl:value-of select="name"/></xsl:attribute>
<xsl:value-of select="name"/>
</td>
<xsl:if test="position() mod 5 = 0">
<xsl:text disable-output-escaping="yes"><tr></xsl:text>
</xsl:if>
</xsl:for-each>
<xsl:if test="position() mod 5 = 1">
<xsl:text disable-output-escaping="yes"><tr></xsl:text>
</xsl:if>
<td align="center" valign="top" style='cursor:hand;' onclick="showMessage( this )" >
<xsl:attribute name="name"><xsl:value-of select="name"/></xsl:attribute>
<xsl:value-of select="name"/>
</td>
<xsl:if test="position() mod 5 = 0">
<xsl:text disable-output-escaping="yes"><tr></xsl:text>
</xsl:if>
</xsl:for-each>
zcjl 2004-10-28
- 打赏
- 举报
用<xsl:if>判断people的position
如果%5的结果等于0，就显示<tr>和</tr>
如果%5的结果等于0，就显示<tr>和</tr>
