一个C语言小程序，请帮助改成C++程序！急！谢谢

[pcwwa]

#include <stdio.h>
main()
{
int a,b,d,min;
printf("Enter two numbers:");
scanf("%d%d",&a,&b);
min=a>b?b:a;
for (d=2;d<min;d++)
if (((a%d)==0)&&((b%d)==0))) break;
if (d==min)
{printf("No common denominators\n");
return 0;
}
printf("The lowest common denominator is %d\n",d);
return 0;
}

[renheihei]

//标准c++程序，用dev c++调试
#include <iostream>
using namespace std;

int main()
{
int a,b,d,min;
cout<<"Enter two numbers:";
cin>>a>>b;
min=a>b?b:a;
for (d=2;d<min;d++)
if ((a%d==0)&&(b%d==0)) break;
if (d==min)
{
cout<<"No common denominators"<<endl;
}
cout<<"The lowest common denominator is"<<endl<<d<<endl;
system("pause");
}

[EternalBlue]

晕～～～～你是想换来干嘛？？？
C++本来就可以兼容C。

[wasoxi]

这个只要把输入输出改一下就行了
其实都差不多的

[pcwwa]

谢谢。一时没写清楚。

要改成使它使用C++风格 的I/O语句。

[Leaveye]

#include <stdio.h>
main()
{
int a, b, d, min;
printf("Enter two numbers:");
scanf("%d%d", &a, &b);
min = a > b? b: a;
for(d = 2; d < min; d++)
if(((a % d) == 0) && ((b % d) == 0))) break;
if(d == min) {
printf("No common denominators\n");
return 0;
}
printf("The lowest common denominator is %d\n", d);
return 0;
}

#include <stdio.h>
main()
{
int a, b, d, min;
cout << "Enter two numbers:";
cin >> a >> b;
min = a > b? b: a;
for(d = 2; d < min; d++)
if(((a % d) == 0) && ((b % d) == 0))) break;
if(d == min) {
cout << "No common denominators\n";
return 0;
}
cout << "The lowest common denominator is " << d << "\n";
return 0;
}

顺便说一句，你的算法有问题。比如输入 3, 6 看看。

[renheihei]

谢谢楼主，今天睡个好觉！！！！！！！！！！！！！