5.8w+
社区成员
- 全部
- .NET Framework
- ASP
- Web Services
- .NET互联网桌面应用
- VB
- 图表区
- 分析与设计
- 组件/控件开发
- AppLauncher
- 问答
请问怎么样读这个XML文件？马上送上分
<?xml version="1.0" encoding="gb2312" ?>
- <configuration vendor="aaa">
- <!--
数据源连接字符串集，页面默认的数据源连接的字符串的名称为default
-->
- <Databaselink>
<datasource name="default">Provider="SQLOLEDB.1";User ID=sa;Password=sql;Data Source=LIXUETAI;Initial Catalog=Northwind</datasource>
</Databaselink>
</configuration>
- <configuration vendor="aaa">
- <!--
数据源连接字符串集，页面默认的数据源连接的字符串的名称为default
-->
- <Databaselink>
<datasource name="default">Provider="SQLOLEDB.1";User ID=sa;Password=sql;Data Source=LIXUETAI;Initial Catalog=Northwind</datasource>
</Databaselink>
</configuration>
...全文
当前发帖距今超过3年，不再开放新的回复
发表回复
GSXiaoXiao 2004-11-01
UP
rickjelly2004 2004-11-01
Dim ds As New DataSet
Dim fs As FileStream
Dim reader As StreamReader
Dim dv As DataView
fs = New FileStream(Server.MapPath("user.xml"), FileMode.Open, FileAccess.Read)
reader = New StreamReader(fs)
ds.ReadXml(reader)
fs.Close()
dv = New DataView(ds.Tables(1))
DataGrid1.DataSource = dv
DataGrid1.DataBind()
Dim fs As FileStream
Dim reader As StreamReader
Dim dv As DataView
fs = New FileStream(Server.MapPath("user.xml"), FileMode.Open, FileAccess.Read)
reader = New StreamReader(fs)
ds.ReadXml(reader)
fs.Close()
dv = New DataView(ds.Tables(1))
DataGrid1.DataSource = dv
DataGrid1.DataBind()
rickjelly2004 2004-11-01
Dim xmldoc As XmlDocument
Dim xmlnode As XmlNode
Dim xmllist As XmlNodeList
Dim xmllist1 As XmlNodeList
Dim user As XmlNode
Dim xe As XmlElement
xmldoc = New XmlDocument
xmldoc.Load(Server.MapPath("user.xml"))
xmlnode = xmldoc.SelectSingleNode("infomation")
xmllist = xmlnode.ChildNodes
xmllist1 = xmllist.Item(0).ChildNodes
For Each user In xmllist1
xe = user
Response.Write(xe.GetAttribute("userid"))
Response.Write(" ")
Response.Write(xe.GetAttribute("password"))
Response.Write("<br>")
Next
Dim xmlnode As XmlNode
Dim xmllist As XmlNodeList
Dim xmllist1 As XmlNodeList
Dim user As XmlNode
Dim xe As XmlElement
xmldoc = New XmlDocument
xmldoc.Load(Server.MapPath("user.xml"))
xmlnode = xmldoc.SelectSingleNode("infomation")
xmllist = xmlnode.ChildNodes
xmllist1 = xmllist.Item(0).ChildNodes
For Each user In xmllist1
xe = user
Response.Write(xe.GetAttribute("userid"))
Response.Write(" ")
Response.Write(xe.GetAttribute("password"))
Response.Write("<br>")
Next
BearRui 2004-11-01
你的连接字符串写在注释里面吗？？？
mymailyy 2004-11-01
上面两个楼的哪一种好呀
huoming1978 2004-11-01
UP！~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~``````````````````````````
kkeemmgg 2004-11-01
DataSet Ds=new DataSet();
Ds.ReadXml(Server(@"这个xml文件"));
DataRow Row=Ds.Tables[0].Rows[0];
string Str=Row[0].ToString();
Ds.ReadXml(Server(@"这个xml文件"));
DataRow Row=Ds.Tables[0].Rows[0];
string Str=Row[0].ToString();
forestyang 2004-11-01
首先用XmlDocument.Load(filename)把它读入XmlDocument文档xmlDoc，
再用xmlDoc.SelectSingleNode得到需要的节点
再用xmlDoc.SelectSingleNode得到需要的节点
