请问怎么样读这个XML文件？马上送上分

[mymailyy]

<?xml version="1.0" encoding="gb2312" ?>
- <configuration vendor="aaa">
- <!--

数据源连接字符串集，页面默认的数据源连接的字符串的名称为default


-->
- <Databaselink>
<datasource name="default">Provider="SQLOLEDB.1";User ID=sa;Password=sql;Data Source=LIXUETAI;Initial Catalog=Northwind</datasource>

</Databaselink>

</configuration>

[forestyang]

首先用XmlDocument.Load(filename)把它读入XmlDocument文档xmlDoc，
再用xmlDoc.SelectSingleNode得到需要的节点

[kkeemmgg]

DataSet Ds=new DataSet();
Ds.ReadXml(Server(@"这个xml文件"));
DataRow Row=Ds.Tables[0].Rows[0];
string Str=Row[0].ToString();

[huoming1978]

UP！~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~``````````````````````````

[mymailyy]

上面两个楼的哪一种好呀

[BearRui]

你的连接字符串写在注释里面吗？？？

[rickjelly2004]

Dim xmldoc As XmlDocument
Dim xmlnode As XmlNode
Dim xmllist As XmlNodeList
Dim xmllist1 As XmlNodeList

Dim user As XmlNode
Dim xe As XmlElement

xmldoc = New XmlDocument
xmldoc.Load(Server.MapPath("user.xml"))

xmlnode = xmldoc.SelectSingleNode("infomation")
xmllist = xmlnode.ChildNodes
xmllist1 = xmllist.Item(0).ChildNodes

For Each user In xmllist1
xe = user
Response.Write(xe.GetAttribute("userid"))
Response.Write(" ")
Response.Write(xe.GetAttribute("password"))
Response.Write("<br>")
Next

[rickjelly2004]

Dim ds As New DataSet
Dim fs As FileStream
Dim reader As StreamReader
Dim dv As DataView

fs = New FileStream(Server.MapPath("user.xml"), FileMode.Open, FileAccess.Read)
reader = New StreamReader(fs)
ds.ReadXml(reader)
fs.Close()

dv = New DataView(ds.Tables(1))
DataGrid1.DataSource = dv
DataGrid1.DataBind()

[GSXiaoXiao]

UP