指针操作的问题?

[lizhenlz]

char *s[] = {"man","woman","girl","boy","sister"} ;
char **q ;
int k = 0 ;
for(k=0 ; k < 5 ; k++)
{
strcpy(?,s[k]); (这里?)
printf("测试") ;
}

s <--> q ? (指针转换)

[Henry0]

空间分配与释放

[xuzheng318]

char *strcpy( char *strDestination, const char *strSource );

int printf( const char *format [, argument]... );

[快乐鹦鹉]

q必须先分配空间啊

[xuzheng318]

意思是说new一个
在s和q之间转换，q只是声明，没有分配内存空间

[goodluckyxl]

#include"iostream.h"
#include <malloc.h>

//Test Code:
void main()
{
char *s[] = {"man","woman","girl","boy","sister"} ;
char **q = new char*[5] ;
int k = 0 ;
for( int i = 0; i < 5; i++ )
{
*(q+i) = s[i]; //不要strcpy考了只要测试这样做
cout<<*(q+i)<<endl;
}
delete[] q;
}

[snowboy1124]

new 在 tc 下不能用的
tc 下的指針不分配空間一樣用，靈活 ， 危險

[fallhunter]

晕

[fallhunter]

//想用copy的话

void main()
{
char *s[] = {"man","woman","girl","boy","sister"} ;
char **q = new char*[5] ;
int k = 0 ;
for( int i = 0; i < 5; i++ )
{
q[i] = new char[sizeof(s[i])];
strcpy(q[i],s[i]);
cout<<*(q+i)<<endl;
}
delete[] q;
}

[fallhunter]

// 忘了释放了：
for ( int i=0; i<5; i++ )
delete[] q[i];

delete[] q;

[goodluckyxl]

snowboy1124(雪夜獨行)

这个问题是在c++中提的 想比是使用支持c++的编译器

[jitian81411]

指针使用的时候记着给它赋值

[youngcs]

应包含#include"string"
void main()
{
char *s[] = {"man","woman","girl","boy","sister"} ;
char **q = new char*[5] ;
int k = 0 ;
for( int i = 0; i < 5; i++ )
{
q[i] = new char[sizeof(s[i])];
strcpy(q[i],s[i]);
cout<<*(q+i)<<endl;
}
delete[] q;
}

[不会种地的老农]

分配不分配空间 完全取决与你要干什 么 啊
是复制 还是 引用啊~