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分享在线等：How do you call a regular member function from a static member function?
如题。
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qrlvls 2004-11-12
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an object pointer.
Example:
staticFunc((CClassName*)this);
pObj->m_memberFunc();
Example:
staticFunc((CClassName*)this);
pObj->m_memberFunc();
qrlvls 2004-11-12
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I will call the member functions by passing a object pointer.
Ailaxya 2004-11-12
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class a{
static void fun(LPARAM param);
void Callfun();
}
void a::CallFun()
{
}
void a::fun(LPARAM param)
{
a *pThis = dynamic_cast<a*>param;
pThis->CallFun();
}
static void fun(LPARAM param);
void Callfun();
}
void a::CallFun()
{
}
void a::fun(LPARAM param)
{
a *pThis = dynamic_cast<a*>param;
pThis->CallFun();
}
fallhunter 2004-11-12
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to
liuleilover(Vietor)
3，请问静态对象怎么实现？
static么？那还是要用到对象指针吧，请教了
liuleilover(Vietor)
3，请问静态对象怎么实现？
static么？那还是要用到对象指针吧，请教了
cxq249 2004-11-12
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刚开始学，不太懂。
liuleilover 2004-11-12
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简单，在静态成员函数参数中传递一个类指针就像this。这样静态成员函数就没意义了。：-）
简单2，将那个regular member 定义成静态的。
简单3，将整个类只实现一个静态对象，在静态成员函数中直接引用。
看来是个新手！
简单2，将那个regular member 定义成静态的。
简单3，将整个类只实现一个静态对象，在静态成员函数中直接引用。
看来是个新手！
How do I pass a pointer-to-member-function to a signal handler, X event callback, system call that sDon't.
Because a member function is meaningless without an object to invoke it on, you can't do this directly (if The X Window System was rewritten in C++, it would probably pass references to objects around, not just pointers to fu
