这是为什么？出现这个错误！！！？？？

[sunauqt]

<?php
$service = array();

$service[] = array(
'cmdkey' => '/^[0-9]{8}$/',
'numkey' => 123456,
'cmd_match' => 1,
'num_match' => 1,
);

$service[] = array(
'cmdkey' => 'A',
'numkey' => '1234',
'cmd_match' => 1,
'num_match' => 1,
);

$cmd = "19780988";
foreach ($service as $svc) {
if(preg_match($svc['cmdkey'],$cmd)) {
echo "ok";
}
}

?>

能显示ＯＫ，但是提示错误：
Warning: Delimiter must not be alphanumeric or backslash
在ＩＦ那一行，是什么原因？

[surfchen]

字符A($service[1][cmdkey]=='A')怎么可能作为pattern？？？？没有定界符

[hahawen]

'cmdkey' => '/^[0-9]{8}$/', 对的
'numkey' => 123456, 错
'cmd_match' => 1, 错
'num_match' => 1, 错

[wxq4100798]

提示是限定符必需为字每或斜杠
$service[] = array(
'cmdkey' => 'A',
'numkey' => '1234',
'cmd_match' => 1,
'num_match' => 1,
);
改为
$service[] = array(
'cmdkey' => '/A/',
'numkey' => '1234',
'cmd_match' => 1,
'num_match' => 1,
);
就对了

[sunauqt]

原来是这里，惭愧！！！