！！！求救－－－serversocket.accept()如何中断？！！！

[uruly]

我写了一个应用程序，它在执行serversocket.accept()时，想中断程序的
执行，点关闭按钮，可是不起作用，应该是因为accept()一直在运行的原因，
请问有什么方法可以让程序可以关闭？
谢谢

[allen830826]

close不行吗？

[funcreal]

把它放在一个线程里面就行了。

[javafaq2004]

这个好像没有肯定的方法做到。

[uruly]

那要怎么办啊

[uruly]

我急用啊

[uruly]

还有没有别的好方法

[fjw3699]

一般做成线程，同时在线程的循环中加一个FLAG进行统一控制

[Avampire]

public class ClientMain{
Server svr = new Server();
public static void main(String args[]){
waitCommand();
}
/**
* 命令等待与采集循环
*/
public void waitCommand() {
svr.start();
BufferedReader commandReader = new BufferedReader(new InputStreamReader(System.in));
while (true) {
try {
String command = commandReader.readLine();
if (command.equals("q")) {
Server .stopServer();
System.exit(0);
}else
System.out.println("you input:"+command);
} catch (Exception e) {
System.out.println("faile in ClientMain.waitCommand:" + e);
}
}
}
//监听线程
public class Server extends Thread {
private ServerSocket listenSocket;
boolean stop = fals;
public void stopServer() {
this.stop = true; // Set the stop flag
this.interrupt(); // Stop blocking in accept()
}
public void run(){
.......
while(!stop){
....
Socket client = listenSocket.accept();
...
}

}
}

[Avampire]

public class ServerMain{
Server svr = new Server();
public static void main(String args[]){
waitCommand();
}
/**
* 命令等待与采集循环
*/
public void waitCommand() {
svr.start();
BufferedReader commandReader = new BufferedReader(new InputStreamReader(System.in));
while (true) {
try {
String command = commandReader.readLine();
if (command.equals("q")) {
Server .stopServer();
System.exit(0);
}else
System.out.println("you input:"+command);
} catch (Exception e) {
System.out.println("faile in ServerMain.waitCommand:" + e);
}
}
}
//监听线程
public class Server extends Thread {
private ServerSocket listenSocket;
boolean stop = fals;
public void stopServer() {
this.stop = true; // Set the stop flag
this.interrupt(); // Stop blocking in accept()
}
public void run(){
.......
while(!stop){
....
Socket client = listenSocket.accept();
...
}

}
}
临时写的，小错就自己改改了