十万火急!!!!!!!!!!!!!!怎样用xmldocument处理调用webservice返回的xml文件啊???
rt.......................
付代码如下:
string URL= "http://211.123.*.*/SmbpHttpAgent/SmbpHttpAgent.asmx/SmbppUserRequestOrderBusiness?bstrUserMsisdn=" + TelNum + "&bstrBusinessCode=" + BusinessNo + "&bstrParameter=" + Params + "";
string result,messageid,businessCode,longcode,Message;
messageid = "";
longcode = "1111";
int row;
MSXML2.XMLHTTPClass objHttp = new MSXML2.XMLHTTPClass();
try
{
objHttp.open("GET",URL,false,null,null);
objHttp.send("");
if (objHttp.readyState == 4)
{
XmlDocument doc = new XmlDocument();
doc.LoadXML(objHttp.ResponseText);//这句能得到返回的xml吗????
XmlNode node = doc.selectsinglenode(....);
}
catch()
{
}
请问上面的程序有没有错啊,我不能进行调试,因为远程web服务要固定ip,而我的是动态ip啊!!